CaI2 --> Ca2+ + 2I-
Complete Ionic Equation. 2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s) Net Ionic Equation Minus the Spectator Ions K+ and I-. Ca2+(aq) + SO42-(aq) --> CaSO4(s)
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
No compounds are metals. All metals are elements, although some metals (e.g. brass) are mixtures of metals.
Unless the equation has an aqueous compound in it, there is no net ionic equation. CaCO3 ====CO2+ CaO becouse its not in an aqueous solution no net ionic is needed you science teacher probably just wants to see if know when to use net ionic equations
The chemical equation is: (K+ + I-)(aq) + (Ag+ + [NO3]-)(aq) --> AgI (s) + (K+ + [NO3]-)(aq) or The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The net ionic equation for the dissolution of solid calcium iodide (CaI2) in water is: CaI2(s) → Ca2+(aq) + 2I^-(aq)
Calcium iodide is an ionic compound. It is formed by the transfer of electrons from calcium to iodine, resulting in the formation of positively charged calcium ions and negatively charged iodide ions, which are held together by electrostatic forces.
Worded Equation; Potassium Iodide + Calcium Chloride ------> Potassium Chloride + Calcium Iodide Chemical Equation; KI (l) + CaCl (l) -----> KCl (aq) + Ca(I)2 (aq) Note Answer is only correct if proper states are applied and used.
Calcium iodide is an ionic compound composed of one calcium ion (Ca2+) and two iodide ions (I-). Therefore, there are a total of 3 ions present in calcium iodide.
Complete Ionic Equation. 2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s) Net Ionic Equation Minus the Spectator Ions K+ and I-. Ca2+(aq) + SO42-(aq) --> CaSO4(s)
The compound formed between calcium and iodine is calcium iodide (CaI2). It is an ionic compound composed of calcium cations (Ca2+) and iodide anions (I-).
Calcium iodide (CaI2) is the compound formed by the combination of calcium and iodine. It is an ionic compound often used in various industrial applications.
Please mention this reaction.
The formula of calcium iodide is CaI2. This is because calcium is a group 2 element with a 2+ charge, while iodide is a group 17 element with a 1- charge. Therefore, to balance the charges, two iodide ions are needed for each calcium ion.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The ionic compound of CaI2 is calcium iodide. It is formed when calcium (Ca) and iodine (I) react to transfer electrons and create an ionic bond, resulting in the compound CaI2.
The net ionic equation is SO42- + Ca2+ CaSO4.