CaI2 --> Ca2+ + 2I-
Complete Ionic Equation. 2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s) Net Ionic Equation Minus the Spectator Ions K+ and I-. Ca2+(aq) + SO42-(aq) --> CaSO4(s)
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
It all dissolves.
Unless the equation has an aqueous compound in it, there is no net ionic equation. CaCO3 ====CO2+ CaO becouse its not in an aqueous solution no net ionic is needed you science teacher probably just wants to see if know when to use net ionic equations
2I- + Pb2+ ? PbI2 (s)
Ca(OH)2_ calcium hydroxide
CaI2
Please mention this reaction.
Complete Ionic Equation. 2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s) Net Ionic Equation Minus the Spectator Ions K+ and I-. Ca2+(aq) + SO42-(aq) --> CaSO4(s)
Potassium iodide is ionic.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
Sodium iodide, like all sodium compounds, is ionic.
It all dissolves.
ioic bonding
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Copper iodide is an ionic compound.
One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide. Ca + I2 ---> I- + Ca2+ + I- ---> CaI2