Complete Ionic Equation.
2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s)
Net Ionic Equation Minus the Spectator Ions K+ and I-.
Ca2+(aq) + SO42-(aq) --> CaSO4(s)
When calcium metal is added to a solution of copper sulfate, a single displacement reaction occurs. The more reactive calcium displaces the less reactive copper from the copper sulfate solution. This results in the formation of calcium sulfate and elemental copper. The balanced chemical equation for this reaction is: Ca + CuSO4 -> CaSO4 + Cu.
The balanced chemical equation for the reaction between CaCO3 (calcium carbonate) and KCl (potassium chloride) is: CaCO3 + 2KCl -> CaCl2 + K2CO3
Ca+2 (aq) + C2O4-2 (aq) + H2O (l) --> CaC2O4 *H2O (s)
The products formed when calcium carbonate reacts with sulfuric acid are calcium sulfate, carbon dioxide, and water. The balanced chemical equation for this reaction is: CaCO3(s) + H2SO4(aq) -> CaSO4(s) + CO2(g) + H2O(l).
The reaction between potassium carbonate and calcium nitrate will result in the formation of potassium nitrate and calcium carbonate. The balanced chemical equation is: K2CO3 + Ca(NO3)2 -> 2KNO3 + CaCO3.
The chemical equation is:K2CO3 + CaCl2 = CaCO3(s) + 2 KCl
The balanced equation for potassium carbonate (K2CO3) reacting with calcium chloride (CaCl2) is: K2CO3 + CaCl2 -> 2KCl + CaCO3 This equation represents the double displacement reaction that occurs between the two compounds.
When calcium metal is added to a solution of copper sulfate, a single displacement reaction occurs. The more reactive calcium displaces the less reactive copper from the copper sulfate solution. This results in the formation of calcium sulfate and elemental copper. The balanced chemical equation for this reaction is: Ca + CuSO4 -> CaSO4 + Cu.
I assume a double displacement reaction. At least ideally. 2KI + CaS -> K2S + CaI2
The balanced equation for calcium chloride is CaCl2. This means that for every calcium atom, there are two chlorine atoms.
The balanced chemical equation for the reaction between CaCO3 (calcium carbonate) and KCl (potassium chloride) is: CaCO3 + 2KCl -> CaCl2 + K2CO3
Ca+2 (aq) + C2O4-2 (aq) + H2O (l) --> CaC2O4 *H2O (s)
Acid is Sulphuric Acid Base is Calcium Oxide. The word equation is Calcium oxide + sulphuric Acid = Calcium sulphate + Water. The Balanced reaction equation is CaO)s) + H2SO4(aq) = CaSO4(s) + H2O(l)
The balanced equation for Calcium Fluoride and sulfuric acid :- CaF2 + H2SO4 = Caso4 + 2HF
Calcium Sulphate and water. The easy way to see this is that you have an acid reacting with an alkali (hydroxides are always alkalis), so the reaction is a neutralisation reaction, meaning that it produces water. This leaves a sulphate ion and a calcium ion, which react to form the salt calcium sulphate.
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
The balanced equation for the reaction between calcium and oxygen to produce calcium oxide is: 2Ca + O2 -> 2CaO