Calcium + Iodine --> Calcium iodide
1 Ca + 1 I2 --Δ--> 1 CaI2
what is the balanced equation for Rubidium metal reacting with halogen iodine
2Al + 3I2 -> 2AlI3
Cl2(g) + 3I2(s) → 2ICl3(l)
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
The chemical equation for the reaction between calcium and iodine is: Ca + I2 -> CaI2.
what is the balanced equation for Rubidium metal reacting with halogen iodine
Balanced:H2 + I2 ----> 2 HI
2Al + 3I2 -> 2AlI3
Cl2(g) + 3I2(s) → 2ICl3(l)
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
The chemical equation for the reaction between calcium and iodine is: Ca + I2 -> CaI2.
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
The chemical equation for magnesium reacting with iodine is: Mg + I2 -> MgI2
The balanced equation for the reaction of cesium with iodine is: 2Cs + I2 -> 2CsI
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
The balanced chemical equation for the reaction between bromine gas (Br2) and calcium iodide (CaI2) is 3Br2 + 2CaI2 → 2CaBr2 + 4I2. The reaction results in the formation of calcium bromide (CaBr2) and elemental iodine (I2).
The balanced equation for the reaction of oleic acid (C18H34O2) and iodine (I2) is: C18H34O2 + 6I2 → C18H33I6O2 + 6HI. This equation shows that one molecule of oleic acid reacts with six molecules of iodine to form one molecule of iodine-substituted oleic acid and six molecules of hydrogen iodide. Balancing the equation ensures that the number of atoms of each element is the same on both sides of the reaction.