2Al + 3I2 -> 2AlI3
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
what is the balanced equation for Rubidium metal reacting with halogen iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
Cl2(g) + 3I2(s) → 2ICl3(l)
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
what is the balanced equation for Rubidium metal reacting with halogen iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
Balanced:H2 + I2 ----> 2 HI
Cl2(g) + 3I2(s) → 2ICl3(l)
the chemical equation of aluminium and iodine is given a s follows :2Al +3 I -> Al 2 I 3.This is a balance eqaution .
The molecular equation is6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2Oand the net ionic is6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
The chemical equation for magnesium reacting with iodine is: Mg + I2 -> MgI2
The balanced equation for the reaction of cesium with iodine is: 2Cs + I2 -> 2CsI
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
The balanced equation for the reaction of oleic acid (C18H34O2) and iodine (I2) is: C18H34O2 + 6I2 → C18H33I6O2 + 6HI. This equation shows that one molecule of oleic acid reacts with six molecules of iodine to form one molecule of iodine-substituted oleic acid and six molecules of hydrogen iodide. Balancing the equation ensures that the number of atoms of each element is the same on both sides of the reaction.
KI would be potassium iodine, but you asked KL, and there is no L element.