2Na2S2O3 + I2 --> 2NaI + Na2S4O6
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
aluminium does not react with water but it reacts with steam
you have to write... 2KI + Cl2 = 2KCl + I2
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The balanced equation for fluorine reacting with sodium iodide is: 2 NaI + F2 → 2 NaF + I2
2KI + F2 ----> 2KF + I2I hope this help :) :P :D :} :]
aluminium does not react with water but it reacts with steam
you have to write... 2KI + Cl2 = 2KCl + I2
The balanced chemical equation for the reaction of hydrogen with fluorine to produce hydrogen fluoride is: 2H2 + F2 → 4HF
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Solid sodium iodide reacts with water to form sodium ions and iodide ions. No further reactions occur because this compound is a salt of a strong acid and a strong base. Thus, the overall reaction is NaI(s)=> Na+ + I-
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
The word equation for the reaction between potassium and iodine is: potassium + iodine → potassium iodide.
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.