The molecular equation is
6 I2 + 12 NaOH = 2 NaIO3 + 10 NaI + 6 H2O
and the net ionic is
6 I2 + 12 OH- = 2 IO3- + 10 I- + 6 H2O
what is the balanced equation for Rubidium metal reacting with halogen iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
2Al + 3I2 -> 2AlI3
Cl2(g) + 3I2(s) → 2ICl3(l)
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
what is the balanced equation for Rubidium metal reacting with halogen iodine
Calcium + Iodine --> Calcium iodide1 Ca + 1 I2 --Δ--> 1 CaI2
Balanced:H2 + I2 ----> 2 HI
2Al + 3I2 -> 2AlI3
Cl2(g) + 3I2(s) → 2ICl3(l)
Aluminium + Iodine ----> Aluminium iodide2 Al + 3 I2 ----> 2 AlI3
6NaOH + 3I2 = 5NaI + NaIO3 + 3H2O Six moles of sodium hydroxide and three moles of diatomic iodine yield five moles of sodium iodide, one mole of sodium iodate, and three moles of water. Cheers!
The chemical equation for magnesium reacting with iodine is: Mg + I2 -> MgI2
When potassium hydroxide reacts with iodine, it forms potassium iodide and potassium iodate. The balanced chemical equation for this reaction is 6 KOH + 3 I2 → 5 KI + KIO3 + 3 H2O.
The balanced equation for the reaction of cesium with iodine is: 2Cs + I2 -> 2CsI
The balanced equation for the reaction of aluminum and iodine to form aluminum iodide is: 2Al + 3I2 -> 2AlI3
The balanced equation for the reaction of oleic acid (C18H34O2) and iodine (I2) is: C18H34O2 + 6I2 → C18H33I6O2 + 6HI. This equation shows that one molecule of oleic acid reacts with six molecules of iodine to form one molecule of iodine-substituted oleic acid and six molecules of hydrogen iodide. Balancing the equation ensures that the number of atoms of each element is the same on both sides of the reaction.