Na is +1 because it is a metal, and its charge is its oxidation number
O is -2 it is more electronegative than Cl, so it takes the electrons (6-8=-2)
Cl is +3 need to make the whole thing neutral (-2*2=-4 -4+1=-3... Cl has to balance it out.)
+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1. Therefore, the single chlorine atom must have an oxidation state of +5 for the total oxidation states to add to zero.+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1
+1 for H -1 for I
The oxidation number of Li in LiNO2 is +1, as it typically has an oxidation number of +1 in its compounds.
+2 for Mg +4 for C -2 for each O
Phosphorus increases its oxidation number in this reaction. In H3PO4, phosphorus has an oxidation number of +5, and in K3PO4, it has an oxidation number of +5 as well. This means that phosphorus's oxidation state remains the same throughout the reaction.
Chlorine has an oxidation number of +7 in perchloric acid (HClO4).
In per chloric acid HClO4, the oxidation number of chlorine is +7.
The oxidation state of Cl in HClO4 is +7. In HClO4, since the oxidation state of H is +1 and that of O is -2, the sum of the oxidation states in the compound must equal 0. Therefore, the oxidation state of Cl in this case is +7.
+1 for H, -2 for each O and +7 for Cl
By charge, I assume you mean oxidation number. Oxygen's oxidation number is a very dependable -2, with only a few strange exceptions. A better question would be "What is chlorine's oxidation number in ClO4-?" The answer would be +7.
It depends on the compound its in. (the range for its oxidation number ranges from -1 to +7 [odd numbers in between are its oxidation numbers exp: -1, +1, +3, +5, +7]) For example if its cl- (only a chlorine ion) then its oxidation number is -1 (simmilar to its valency). If its in the compound NaCl, We know that its total oxidation is 0. (all compunds have an oxidation number of zero) Na has an oxidation number +1. Therefore +1 + x = 0 -> through this you can find the oxidation number of chlorine in this compund. (x representing the oxidation number of chlorine). In this case the answer is x=-1. In the compound HClO4 (perchloric acid), the oxidation number of the total compund is equal to 0. Oxygen has an oxidation number of -2, and hydrogen has an oxidation number of +1. Therefore, (+1) + x + (-2*4) = 0 (oxygen in this compund has 4 atoms so -2 multiplied by 4) Thus: +1 + x + (-8) = 0 +1 + x = 8 x= 8 -1 x= +7 So we can see here that the oxidation number of chlorine has become +7. Do the same for any compound that chlorine is involed in. Hope it helps.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1. Therefore, the single chlorine atom must have an oxidation state of +5 for the total oxidation states to add to zero.+5. In oxyacids, oxygen has an oxidation state of -2 and hydrogen an oxidation state of +1
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.