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In a reverse fault, the oldest rocks will be at the bottom of the fault plane, while the youngest rocks will be at the top. This is because reverse faults form when compressional forces cause rocks to be pushed together and up, resulting in older rocks being thrust over younger ones.

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What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?

The relative age of the fault is younger than the sedimentary rock layers it cuts across. The fault must have formed after the deposition of the sedimentary rock layers, as it disrupts them.


If a fault occurs in an area where rock layers have been folded what type fault would it be?

What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==


Why is the age of a fault is younger than the rocks in which it is found?

How could the rock be faulted if it came after the faulting? It wouldn't be there to fault. So therefore, what ever the fault cuts through, it must be younger than it in order for it to be able to cut the rock in the first place.


Why is the age of a fault younger than the rocks in which it was found?

The fault must be younger because it cuts across the existing rocks, indicating that it formed after the rocks were already in place. This suggests that the faulting event occurred after the deposition of the rock layers.


A fault can be useful in determining which group of rocks?

A fault can be useful in determining the relative ages of different rock layers by showing which layers have been displaced or shifted due to tectonic forces. This can help geologists establish the sequence of events in an area's geological history.

Related Questions

What is the rock age of the normal fault?

The rock age of a normal fault can be determined by analyzing the age of the rocks on either side of the fault. Normal faults typically form in response to extensional forces, where older rocks are uplifted and younger rocks are deposited in the hanging wall. By dating the rocks on either side of the fault, geologists can determine the relative timing of fault movement.


What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?

The relative age of the fault is younger than the sedimentary rock layers it cuts across. The fault must have formed after the deposition of the sedimentary rock layers, as it disrupts them.


Why is the age of the fault younger than the rock in which it is found?

100 year old


Why is the age of a fault younger than the rock in which it is found?

100 year old


How might a geologist use relative dating to determine when the fault occured?

The Law of Cross-Cutting Relationships would be used here. If a fault cuts across a rock unit, it is younger than that rock unit. If a fault cuts across a series of rocks, but suddenly stops at a rock unit, then that rock unit which the fault stops at is younger than the fault. So let's say the order of rocks (from top to bottom), is A B C D. If the fault cuts across B C and D, but not A, then the age of the fault is sometime between A and B. If you know the absolute ages of A and B (let's say, rock A is 100 million years old and rock B is 200 million years old), then the age of the faulting is between 100 and 200 million years ago.


Why is the age of a fault in a rock younger in which it is found?

Given the law of superposition and assuming an undisturbed "pancake" stratigraphy each successive layer is younger than the the underlying one. Therefore, the fault is the 'youngest' feature in the system because the rocks need to form first in order for a fault to truncate them.


What is the relative age of a fault or igneous intrusion that cuts through an unconformity?

The relative age of a fault or igneous intrusion that cuts through an unconformity is younger than the unconformity but older than the rock it cuts through. This is because the fault or intrusion must have formed after the deposition of the rock layers below the unconformity but before the deposition of the rock layers above the unconformity.


If a fault occurs in an area where rock layers have been folded what type fault would it be?

What is the relative age of a fault that cuts across three horizontal sedimentary rock layers?A. The fault is older than the middle layer. B.The fault is younger than all the layers it cuts across.C. The fault is the same age as the top layer. D. The fault is older than all the layers it cuts across == ==


Why is the age of a fault is younger than the rocks in which it is found?

How could the rock be faulted if it came after the faulting? It wouldn't be there to fault. So therefore, what ever the fault cuts through, it must be younger than it in order for it to be able to cut the rock in the first place.


How are the layers of rock if they are undisturbed?

The undisturbed rock layers are horizontal and in order of age from youngest nearest the surface to oldest at the bottom of the rock unit.


How can you use fossils and geologic features interpret the relative age of rock layers?

Fossils can be used to determine the relative age of rock layers by comparing the types of fossils found in different layers. Fossils of organisms that existed for a short period of time can be used to date layers of rock containing them. Geologic features such as fault lines and unconformities can also help determine the relative age of rock layers by showing where layers have been disturbed or eroded.


How does the age of a fault compare to the age of the rocks that are actually faulted?

The fault will be younger than the rocks it faulted (cross-cutting relationships).