iron(II) hydroxide + phosphoric acid
3Fe(OH)2 + 2H3PO4 => Fe3(PO4)2 + 6H2O
H3po4+ 3nh4oh -> 3h2o + (nh4)3po4
The balanced equation is 3 Ca(OH)2 + 2 H3PO4 -> Ca3(PO4)2 + 6 H2O.
The equation is NH4OH + HBr -> NH4Br + H2O.
We know that sodium hydroxide (NaOH) is a base and that phosphoric acid (H3PO4) is an acid. The balanced equation for the reaction is: 3NaOH + H3PO4 -----> Na3PO4 + 3H2O Remember that all bases react with acids in what is called an acid-base reaction. The result is the formation of a salt and water. Try working out other reactions like this yourself.
Phosphoric Acid dissociates to give off 3H+ ions, meaning that one mole of Phosphoric acid reacts with three mols of sodium hydroxide. Using the equation n = c x v n = 0.1 x 0.05 =0.005 mols of OH ions in the solution therefore there are 0.005/3 = 0.00167 So the volume of phosphoric acid - v = n/c v = 0.00167/0.2 v = 0.00835 l = 8.4ml of Phosphoric Acid reacts completely with Sodium hydroxide
Pa
3CsOH(aq) + H3PO4(aq) --> Cs3PO4(aq) + 3H2O(l)
2H3PO4(aq) + 3Ba(OH)2(aq) > Ba3(PO4)2(aq) + 6H2O(l)
the balanced equation for ammonium hydroxide and perchloric acid is given below.NH4OH (aq) + HCl (aq) ---> NH4Cl (aq)+ H2O (l) .Above is the balanced molecular Equation.
H3po4+ 3nh4oh -> 3h2o + (nh4)3po4
3Ca(OH)2+2H3PO4 = Ca3(PO4)2+6H2O
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
6Na + 2H3PO4 = 2Na3PO4 + 3H2
Hi + oh- ---> h2o + i-
Usually these reaction are done with a substantial excess of NaOH. You would getH3PO4 + 3NaOH --> Na3PO4(aq) + 3HOH.
P2o5+3h2o--->2h3po4
A balanced equation has equal numbers of each type of atom on each side of the equation.The Balanced Ionic equation for Nitrous acid and sodium hydroxide is as follows .Nitrous acid is a weak acid so it does not completely dissociate in water. So you can write for the net ionic equation :HNO2 + OH- ---> NO2- + H2O