h2+i2=2hi
The balanced equation for the reaction between hydrogen gas (H2) and iodine gas (I2) to form hydrogen iodide gas (HI) is: H2 + I2 → 2HI
Balanced:2 HI ----> H2 + I2
Balanced:H2 + I2 ----> 2 HI
KI + H2SO4 (concentrated) --> HI + KSO4
The reaction between hydrogen gas and iodine vapor forms hydrogen iodide gas. The balanced chemical equation for this reaction is: H2(g) + I2(g) -> 2HI(g)
The balanced equation for the reaction between hydrogen gas (H2) and iodine gas (I2) to form hydrogen iodide gas (HI) is: H2 + I2 → 2HI
The chemical formula for hydrogen is H2, and for iodine is I2.
Balanced:2 HI ----> H2 + I2
Balanced:H2 + I2 ----> 2 HI
HI will be consumed. The reaction will proceed to the left. More I2 will form.
KI + H2SO4 (concentrated) --> HI + KSO4
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
The reaction between hydrogen gas and iodine vapor forms hydrogen iodide gas. The balanced chemical equation for this reaction is: H2(g) + I2(g) -> 2HI(g)
If the volume of the reaction vessel is decreased, the reaction will shift towards the side with fewer gas molecules to relieve the pressure. In this case, since there are 3 moles of gas on the left side (H2 and I2) and only 2 moles of gas on the right side (2HI), the reaction will shift to the right to decrease the pressure, producing more HI.
H2, N2, O2, F2, Cl2, Br2, and I2
The brown color in the bottle of pure HI is likely due to the slow decomposition of the hydrogen iodide (HI) into iodine (I2) and hydrogen gas (H2). This reaction can be catalyzed by light, heat, or impurities in the HI solution. The formation of iodine can give the solution a brown color.
This is a combination reaction, where two or more substances combine to form a single product. In this case, hydrogen gas (H2) and iodine gas (I2) react to form hydrogen iodide gas (2HI).