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First you need the formula for the two starting ingredients. Sodium hydroxide is NaOH and Tartaric acid is HOOC--CH(OH)--CH(OH)--COOH. This can be found by looking at for example, the related link. Other searches will show that NaOH reacts with a carboxylic acid thus: -----COOH + NaOH -----> COONa +H2O in general terms.

So putting all this information together we know that 2 molecules of NaOH will be needed per molecule of tartaric acid. So the final reaction equation is

HOOC-CH(OH)-CH(OH)-COOH +2NaOH ----> NaOOC-CH(OH)-CH(OH)-COONa + 2H20

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