A White precipitate would be obtained.
Add the compound to nitric acid untill the solution is near colourless, then following this add 2-3 drops of silver nitrate, if a white precipitate forms then the chloride ion is present. to identify if the Cation is lead, try doing a flame test with an emission spectra. cl- + ag+ ---> AgCl
Put a little hydrochloric acid in the water sample. 2HCl + Pb -> H2 + PbCl2. Lead chloride is insoluble and its density is much higher than that of water. You can then perform a test on the precipitate to determine the ratio of lead chloride to silver chloride in your precipitate.
Lead (IV) Iodide [PbO2] is black.- Chloe E.
When solutions of sodium chloride and lead chloride are mixed, a precipitation reaction occurs. Lead chloride is less soluble than sodium chloride, so lead chloride precipitates out of the solution as a solid, while sodium chloride remains dissolved. This results in the formation of a white precipitate of lead chloride.
The net ionic equation for barium chloride (BaCl2) and lead acetate (Pb(C2H3O2)2) is Ba²⁺ + 2C2H3O2⁻ → Ba(C2H3O2)2. This equation represents the formation of barium acetate as a solid precipitate when barium chloride and lead acetate are mixed together.
When solutions of lead(II) nitrate (Pb(NO3)2) and potassium chloride (KCl) are mixed, a precipitate of lead(II) chloride (PbCl2) will form. This is because lead(II) chloride is insoluble in water and will precipitate out of the solution.
The products of the reaction between lead(II) nitrate and sodium chloride are lead(II) chloride and sodium nitrate, which are both soluble in water. This reaction forms a white precipitate of lead(II) chloride.
Lead (II) chloride is insoluble in water. It forms a white precipitate when mixed with water.
Yes, a white precipitate of lead(II) chloride will form when you mix solutions of potassium chloride and lead nitrate due to the insolubility of lead(II) chloride. The balanced chemical equation for this reaction is: Pb(NO3)2 + 2KCl → PbCl2 + 2KNO3
Yes, a precipitation reaction occurs when potassium chloride is mixed with lead(II) acetate. Lead(II) chloride, a white precipitate, forms in the solution due to the insolubility of lead(II) chloride in water.
Yes; lead(II) chloride is very low soluble in water.
Add the compound to nitric acid untill the solution is near colourless, then following this add 2-3 drops of silver nitrate, if a white precipitate forms then the chloride ion is present. to identify if the Cation is lead, try doing a flame test with an emission spectra. cl- + ag+ ---> AgCl
The reaction is: 2 NaCl + Pb(NO3)2 = 2 NaNO3 + PbCl2 The lead (II) chloride is a precipitate insoluble in water.
Put a little hydrochloric acid in the water sample. 2HCl + Pb -> H2 + PbCl2. Lead chloride is insoluble and its density is much higher than that of water. You can then perform a test on the precipitate to determine the ratio of lead chloride to silver chloride in your precipitate.
Lead chloride can be made by reacting hydrochloric acid with lead(II) nitrate or lead(II) oxide. This reaction forms lead chloride as a white precipitate. It is important to conduct this reaction in a well-ventilated area and handle lead compounds with care due to their toxic nature.
yellow
Lead iodide (PbI2) is a compound consisting of lead and iodine, whereas silver chloride (AgCl) is a compound made up of silver and chlorine. Lead iodide is yellow in color and is more soluble in water compared to silver chloride, which is white in color and has low solubility in water. Lead iodide has different chemical and physical properties compared to silver chloride, due to the different elements it contains.