Add the compound to nitric acid untill the solution is near colourless, then following this add 2-3 drops of silver nitrate, if a white precipitate forms then the chloride ion is present. to identify if the Cation is lead, try doing a flame test with an emission spectra.
cl- + ag+ ---> AgCl
PbCl2 is lead chloride, lead dichloride or lead (II) chloride. It is an important to the chemical industry because of its value as a reagent. A link to the Wikipedia article is provided. Surf on over for details.
lead II acetate and barium chloride equation
PbCl2 is lead(II) chloride, PbCl4 is lead(IV) chloride
Sodium chloride remain in solution; lead(II) chloride is practically insoluble in water.
A White precipitate would be obtained.
PbCl2 is lead chloride, lead dichloride or lead (II) chloride. It is an important to the chemical industry because of its value as a reagent. A link to the Wikipedia article is provided. Surf on over for details.
lead II acetate and barium chloride equation
PbCl2 is lead(II) chloride, PbCl4 is lead(IV) chloride
Sodium chloride remain in solution; lead(II) chloride is practically insoluble in water.
PbCl2 is the molecular formula (not chemical equation) of lead(II) chloride.
Insoluble
A filter? Lead (II) chloride isn't very soluble (and lead (IV) chloride isn't very stable, tending to decompose into lead (II) chloride and chlorine gas), and you could use HCl to raise the chloride concentration (and therefore lower the lead concentration) even further.
Lead(ii) Iodide is a yellow precipitate while silver chloride is white.
Yes; lead(II) chloride is very low soluble in water.
Lead (II) chloride is obtained - an insoluble salt in water - and sodium acetate.
PbCl2 --> Pb2+ + Cl-
The reaction is: 2 NaCl + Pb(NO3)2 = 2 NaNO3 + PbCl2 The lead (II) chloride is a precipitate insoluble in water.