Pb(NO3)2(aq) + K2SO4(aq) = PbSO4(s) + 2KNO3(aq)
The Lead(II) Sulphate formed (i.e. PbSO4(s)) is obtained as a white precipitat. Potassium Nitrate solution (KNO3(aq)) is colourless.
The chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium sulfate (K2SO4) is Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3. It forms barium sulfate (BaSO4) and potassium nitrate (KNO3) as the products.
Yes, a precipitate of barium sulfate will form because barium ions (Ba²⁺) from barium nitrate react with sulfate ions (SO₄²⁻) from potassium sulfate to form an insoluble compound, barium sulfate (BaSO₄). This insoluble compound will precipitate out of solution.
2Fe(NO3)3 + 3Na2SO4 -> Fe2(SO4)3 + 6NaNO3
The two solutions likely contained ions that reacted together to form a solid compound. In this case, mixing solutions of potassium sulfate (containing potassium and sulfate ions) and calcium nitrate (containing calcium and nitrate ions) led to a reaction where calcium ions from calcium nitrate bonded with sulfate ions from potassium sulfate to form calcium sulfate solid.
The complete net ionic equation for the reaction between copper sulfate and lead nitrate is: Cu²⁺(aq) + SO₄²⁻(aq) + 2Pb²⁺(aq) + 2NO₃⁻(aq) → PbSO₄(s) + Cu(s) + 2NO₃⁻(aq)
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
When lead (II) nitrate and potassium sulfate are mixed, they will undergo a double displacement reaction. The products of this reaction are lead (II) sulfate and potassium nitrate. This can be represented by the chemical equation: Pb(NO3)2 + K2SO4 -> PbSO4 + 2KNO3.
No reaction will occur between Potassium Sulfate and Ammonium Nitrate.
The chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium sulfate (K2SO4) is Ba(NO3)2 + K2SO4 -> BaSO4 + 2KNO3. It forms barium sulfate (BaSO4) and potassium nitrate (KNO3) as the products.
The net ionic equation for potassium sulfate (K2SO4) and lead nitrate (Pb(NO3)2) is: Pb^2+(aq) + SO4^2-(aq) -> PbSO4(s)
Ammonium sulphate and potassium nitrate do not react. All that will happen is that the solution will contain separate ammonium, sulphate, potassium, and nitrate ions dissolved in an aqueous (water) solution.
The reaction between lead(IV) nitrate and potassium sulfate would produce lead(IV) sulfate and potassium nitrate. This is because lead(IV) has a 4+ charge, while sulfate has a 2- charge, which leads to a 2:1 ratio of lead(IV) to sulfate ions needed for a balanced equation. The same applies for potassium and nitrate ions.
When sulfuric acid reacts with potassium nitrate, it forms potassium sulfate, nitric acid, and water.
When Lithium nitrate and Potassium sulfate are mixed, they will exchange ions to form Lithium sulfate and Potassium nitrate. This reaction is a double displacement reaction, where the cations of one compound switch places with the cations of the other compound. This results in the formation of two new compounds.
The ionization equation for potassium sulfate (K2SO4) in water is: K2SO4 (s) -> 2K+ (aq) + SO4^2- (aq)
Yes, a precipitate of barium sulfate will form because barium ions (Ba²⁺) from barium nitrate react with sulfate ions (SO₄²⁻) from potassium sulfate to form an insoluble compound, barium sulfate (BaSO₄). This insoluble compound will precipitate out of solution.
2Fe(NO3)3 + 3Na2SO4 -> Fe2(SO4)3 + 6NaNO3