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1.79g/L ( I have the same textbook)

Q: What is the density of NO2 Gas at 0.97 ATM and 35 degree Celsius?

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Density = (Pressure)(Molar Mass)/(R)(Temperature) I forget exactly what R is called, but it is a constant. So, you get (.970)(46)/(.0821)(308). Your final answer is 1.76456. Round to as many decimal places as your teacher prefers

That depends a lot on the pressure - at higher altitudes (less pressure), the boiling point is lower. At standard pressure (1 atm.), the answer is 100 degree Celsius.

If it is an ideal gas, then 0.409 ATM. The governing equation is pv=nrt. Everything on the right side of the equation is constant so pv = constant. Therefore: p1v1 = p2v2 (0.7atm)(3.8L) = p2(6.5L) p2 = 0.409 ATM

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water boils at zero degrees then atmospheric pressure will be...........

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At 4 degrees Celsius and 1 Atm pressure, the density of pure water is 1 gram per cc.

The density is 0,1 g/L.

Density = (Pressure)(Molar Mass)/(R)(Temperature) I forget exactly what R is called, but it is a constant. So, you get (.970)(46)/(.0821)(308). Your final answer is 1.76456. Round to as many decimal places as your teacher prefers

The Celsius scale was created so that 0 was defined as water's freezing point and that 100 was defined as water's boiling point (at 1 ATM of preasure). /\ (that means "delta" or "change of/in") /\ 1C = /\1.8F So if the temp increases by 1 degree celsius, then that is a 1.8 degree increase Fahrenheit .

Solid under standard pressure and temperature conditions (0 degree Celsius, 273 K, and 1 atm)

That depends a lot on the pressure - at higher altitudes (less pressure), the boiling point is lower. At standard pressure (1 atm.), the answer is 100 degree Celsius.

The volume is 13,64 L.

8.51 g/l at standard temperature (0 degrees Celsius,) but 7.93 g/l at room temperature (20 degrees Celsius). 1.251 g/l * 1 ATM / (100 psi * .0680459639 ATM/psi) = 8.51 g/l 1.251 g/l * 1 ATM / (100 psi * .0680459639 ATM/psi) / (293 K / 273 K) = 7.93 g/l

Water boils at 100C at 1 ATM

0.001307 g/cm3 See the related link below from Wolfram|Alfa to confirm.

The water is in the gas phase.

It would be -221.7 deg C.