What is the density of oxygen in grams per liter at 25 degrees celsius amd 0.850atm?

Answer 1

The density is 1.11 grams per liter. You find this density by using the formula N equals P x V/R x T, where N is the number of oxygen moles, P is pressure or 0.850 atm, V is volume assumed as 1 liter, R or the gas constant is 0.0821 Lm/Kmol, and T is the temperature in Kelvin degrees 298 K. The number of oxygen moles found is 0.0347 moles per liter , which is converted to grams per liter by multiply this by 32.0 g O2/1 mol O2.

Answer 2

Using d= MP/RT where d is density (0.275 g/L) M=molar mass of O2 (32.00 g/mol), R (gas constant)=0.0821, T=273+25=298 Kelvin, and pressure is unknown, we solve for P and find that oxygen is at a pressure of 0.210 ATM or 21.3 kPa. With n=m/M, we find that the number of moles (n) of 5000 g of oxygen is 156.25. Plugging these values into PV=nRT, we get a volume of 18 213 Litres.

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