The density of water at 13 0C is 0,999 34 g/cm3.
a temperature. it is 66.67 degrees celcius
When it is night on Mercury, it's colder than earth at any given time,but during the day,obviously,there is no comparison,the earth is much colder. BY THE WAY:this is coming from a 13 year old ;) but one that knows her sh*t.
Diplodocus lived during the Late Jurassic period, around 154-152 million years ago.
In Canada, the smallest license plate size is a motorcycle plate, measuring approximately 152 mm by 102 mm (6 inches by 4 inches).
It is 0.000,000,000,066. 152 pm = 1.52 x 10-10 m
It's 152 degrees Celsius.
To go from Celsius to Fahrenheit:Begin by multiplying the Celsius temperature by 9.Divide the answer by 5.Now add 32.-> 152 Celsius x 9 = 1368-> 1368 / 5 = 273.6-> 273.6 + 32 = 305.6 Fahrenheit
a temperature. it is 66.67 degrees celcius
To find the volume of the gas at 152°C, you can use the Charles's Law equation, V1/T1 = V2/T2, where V1 is the initial volume (262 mL), T1 is the initial temperature (-35.0°C), V2 is the final volume (unknown), and T2 is the final temperature (152°C). Plug in the values and solve for V2 to find the volume of the gas at 152°C.
28 degrees
Table sugar or sucrose melts at about 186°C (367°F).
Cheongwon's population density is 152 people per square kilometer.
The population density of Alanya is 152 people per square kilometer.
the average temperature on Jupiter is about -121 degrees Celsius (152. 15K) with its lowest temperature at-165 degrees Celsius (110.15K).The temperature of Jupiter at the top of its clouds is about -145 degrees celsius, the temperature at its core is about 24 000 degrees celsius. Hope this helps the average temperature on Jupiter is -166° F or -110° C.
there is no dang boiling point
To find the volume of 2.5 mol of hydrogen gas, we can use the Ideal Gas Law equation: PV = nRT. We are given the pressure (152 kPa), temperature (-20.0 degrees Celsius which is equivalent to 253.15 K), and the number of moles (2.5 mol). We can rearrange the equation to solve for volume (V), V = (nRT)/P. Plugging in the values, V = (2.5 mol x 8.314 J/mol·K x 253.15 K) / 152 kPa = 3.51 L. Therefore, 2.5 mol of hydrogen gas will occupy a volume of 3.51 liters at -20.0 degrees Celsius and 152 kPa.
That point is in Australia, near the east coast and about 65 miles north of Newcastle.