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What is the empirical formula of the compound that is 75 carbon and 25 hydrogen?
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
What is the empirical formula of silicon hydride?
The empirical formula of silicon hydride is SiH4. This formula represents the simplest whole number ratio of silicon to hydrogen atoms in the compound.
Is the formula for methane both a molecular and an empirical formula?
Yes, the formula for methane (CH4) is both a molecular formula and an empirical formula. The molecular formula shows the actual number of each atom in a molecule (4 hydrogen atoms and 1 carbon atom), while the empirical formula gives the simplest whole-number ratio of atoms in a compound (CH4).
What is the empirical formula for C3H5?
The empirical formula is C3H5. The answer does not change from the given form because there is no common denominator to divide by.
Does C7 H14 and C10 H20 have the same empirical formula?
Yes, they have. Empirical Formula is the simplest formula of a compound. For both C7H14 and C10H20 the Empirical formula is CH2 .
What is the formula for hydrocarbon containing two hydrogen?
CnH2n + 2)
The empirical formula for cumene a compound containing only carbon and hydrogen is C3H4. Its Molecular mass is 120 g. What is the molecular formula for cumene?
This molecular formula is C9H12.
What is the empirical formula of a molecule containing 24 carbon 6 hydrogen and 70 chlorine?
The empirical formula of the molecule is CHCl₂. This is obtained by dividing the number of atoms of each element by their greatest common factor, leading to a ratio of 1 carbon, 1 hydrogen, and 2 chlorine atoms.
alkanes?
Hydrocarbon molecules containing no functional groups and the formula CnH2n+2 when fully saturated with hydrogen. examples, methane, ethane, butane, octane, isooctane
The combustion data for an unknown compound containing carbon hydrogen and oxygen was analyzed and the empirical formula for the unknown was found to be C3H5O The molar mass of the unknown was found?
To find the molecular formula from the empirical formula (C3H5O) and molar mass, you need to calculate the molar mass of the empirical formula. Then, divide the molar mass of the unknown compound by the molar mass of the empirical formula to get a ratio. Finally, multiply the subscripts in the empirical formula (C3H5O) by this ratio to determine the molecular formula of the unknown compound.
What is the empirical formula for the molecule?
An empirical formula is a chemical formula containing only the number of atoms why is formed (ex.: C6H12), without any indication about the structure.
What is an empirical formula for the molecule?
An empirical formula is a chemical formula containing only the number of atoms why is formed (ex.: C6H12), without any indication about the structure.
What is the empirical formula of the compound that is 75 carbon and 25 hydrogen?
The empirical formula of a compound is the simplest whole number ratio of the elements in the compound. In C75H25, the ratio of carbon to hydrogen is 75:25, which is equal to 3:1. Thus, the empirical formula is C3H.
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What are the element in butane?
Carbon & hydrogen are the two types of elments of the present in butane.
An organic compound only contain hydrogen and carbon is called?
Hydrocarbon, it's kind of simple if you think about it.
What is the empirical formula for a molecule containing 46.8 Is and 53.2 O?
Si2O3
