63.0 X 0.789 = 49.7g
To find the volume of 85.5g of ethanol, you need to know the density of ethanol. The density of ethanol is approximately 0.789 g/mL at room temperature. You can divide the mass of ethanol (85.5g) by its density (0.789 g/mL) to find the volume in milliliters.
According to the CRC Handbook, 70th edition, the density of 94% ethanol is 0.8070 g/ml and the density of 96% ethanol is 0.8013 g/ml. We can interpolate to find that the 95% ethanol should be 0.8042 g/ml.
The total volume of the solution is 48 mL + 144 mL = 192 mL. The percent by volume of ethanol is calculated as (volume of ethanol / total volume of solution) * 100%. Plugging in the values, we get (48 mL / 192 mL) * 100% = 25%. So, the solution contains 25% ethanol by volume.
The density of ethanol is 0.789 g/mL. So 19.6 mL of ethanol weighs 0.789 g/mL * 19.6 mL = 15.464 g. The molar mass of ethanol is 2*12.011 + 6*1.008 + 15.999 = 46.069 g/mol. So, in 15.464 grams, there are 15.464 g / 46.069 g/mol = 0.33567 moles In one mole, there are 6.022*1023 molecules, so we have: 0.33567 moles * 6.022*1023 molecules/mole= 2.0214*1023 molecules. Using correct significant digits, that gives: 2.02*1023 molecules (or particles).
The mass of 225 g of ethanol would be 225 g. The information given about the density of ethanol is not relevant to finding the mass of the given amount (225 g) of ethanol.
15.5 gram ethanol x 1 mL/0.789 (density) = 19.65 mL the density of ethanol is 0.789g/mL
At STP, pure ethanol has density 0.789g/mL. 25 mL will have mass25 (mL) * 0.789 (g/mL)=19.725 g. Round this to 19.7g for three significant figures.
Divide by the density of ethanol.Assuming that it is a total mass of 60.354 grams, and the density of ethanol is 0.789 grams per cm3 (or grams per mL), then the volume of that much ethanol is:60.354 grams ÷ 0.789 grams/mL = 76.494 mL
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The volume of 495g of ethanol can be calculated by dividing the mass by the density of ethanol. The density of ethanol is approximately 0.789 g/ml at room temperature. Therefore, the volume of 495g of ethanol would be 495g / 0.789 g/ml ≈ 627 ml.
To find the volume of 85.5g of ethanol, you need to know the density of ethanol. The density of ethanol is approximately 0.789 g/mL at room temperature. You can divide the mass of ethanol (85.5g) by its density (0.789 g/mL) to find the volume in milliliters.
The volume of 75.0g of ethanol can be calculated using the density of ethanol, which is about 0.789 g/mL at 20°C. By dividing the mass by the density, we find that the volume would be approximately 95.1 mL.
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
Benzene is more dense than ethanol. This can be determined by calculating the density of each liquid using the formula density = mass/volume. In this case, benzene's density is higher than ethanol's because for the same volume, benzene has a higher mass.
To find the product, multiply 630 mmHg by 32.0 mL: (630, \text{mmHg} \times 32.0, \text{mL} = 20160, \text{mmHg⋅mL}).
The solubility of the substance in ethanol can be calculated by dividing the mass of the substance (g) by the volume of ethanol (mL) to get the concentration in units of g/mL. This concentration represents the maximum amount of substance that can dissolve in the given volume of solvent at the specified conditions, forming a saturated solution.
1. Extract 959,6 mL from the 99 % solution. 2. Add 40,4 mL water.