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A properly written formula for the compound, using the subscript fonts available for answers but not for questions, is Al2(SO4)3. This formula shows that there are 2 aluminum atoms, three sulfur atoms, and twelve oxygen atoms in each formula unit, for a total of 342.14 grams per formula unit. 647 of these formula units will have a mass of 647 X 342.14 gramsor 221 kilograms, to the justified number of significant digits.
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What is the formula name for Aluminum sulfate?
Aluminum sulfate is formulated by Al2(SO4)3
What is the mass of 0.25 moles of aluminum sulphate?
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
What is the empirical formula for aluminum sulfate?
The empirical formula for aluminum sulfate is Al2(SO4)3.
What is the symbol for aluminum sulphate?
Aluminium Sulphate= Al2(SO4)3
How many moles of sulfur are present in 3.5 moles of Al2 SO4?
Al2 SO4(wrong) this is how it should be written Al2(SO4)3This how you do it3.5 moles Al2(SO4)3 x 3 mole Sulfur / 1 moles Al2(SO4)3 = put that in ur calculator it will give u the answer
How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
What is the formula name for Aluminum sulfate?
Aluminum sulfate is formulated by Al2(SO4)3
What is the mass of 0.25 moles of aluminum sulphate?
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
What is the name of AL2 (SO4)3?
The name of Al2(SO4)3 is aluminum sulfate.
How do you find out how many oxygen atoms are in 4.70 g of Al2 SO4 3?
How many moles are in 4.70g of NH3?
6.7 grams of aluminum sulfate to moles?
To convert grams of aluminum sulfate to moles, you first need to determine the molar mass of aluminum sulfate (Al2(SO4)3), which is approximately 342.15 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 6.7 grams of aluminum sulfate is approximately 0.02 moles.
How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
How many grams are in 2.4 moles of SO4?
To find the grams in 2.4 moles of SO4, you need to multiply the number of moles by the molar mass of SO4 (sulfate). The molar mass of SO4 is 96.06 g/mol. Therefore, 2.4 moles of SO4 would be 2.4 moles * 96.06 g/mol = 230.544 grams.
What is the formula mass for Al2(SO4)3?
To calculate the formula mass of Al2(SO4)3, we need to determine the molar masses of each element and multiply them by the respective subscripts in the formula. The molar mass of aluminum (Al) is 26.98 g/mol, sulfur (S) is 32.06 g/mol, and oxygen (O) is 16.00 g/mol. Therefore, the formula mass of Al2(SO4)3 is 2(26.98) + 3(32.06 + 4(16.00)) = 342.15 g/mol.
What is the empirical formula for aluminum sulfate?
The empirical formula for aluminum sulfate is Al2(SO4)3.
