Depends on the length the light traveled through the solution and the solution concentration.
molar absorption = absorbance/(length x concentration)
length is typically in cm and concentration is typically in mol/L
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The empirical formula for cupric sulfate pentahydrate is CuSO4·5H2O. It consists of one copper (Cu) atom, one sulfur (S) atom, four oxygen (O) atoms, and five water (H2O) molecules.
Most people think that Cupric sulfate or Copper(II) sulfate, is blue in colour. But actually it is not. Blue colour in Copper(II) sulfate is due to the presence of Water molecules in it. This form is called Copper(II) sulfate Pentahydrate[CuSO4.5H2O], which most people see. If it does not have any water molecules in it, the thing is in pure state and is White in colour. This form is Anhydrous Copper(II) sulfate[CuSO4]. This form is rarely seen, because it can absorb water itself from the nature and become blue in colour. So from this we know that very pure Copper(II) sulfate is not blue, But its Pentahydrate form is blue.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
Copper(II) sulfate has the formula CuSO4.
PbCu2
Formula: CuSO4.5H2O
Yes, it is
The most common form is the pentahydrate.
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
No, copper II sulfate pentahydrate does not sublime. Sublimation is the process of a substance transitioning directly from a solid to a gas without passing through the liquid phase, and copper II sulfate pentahydrate decomposes before it can sublime.
To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.