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Compound made from 63.50 silver 8.25 nitrogen and 28.25 oxygen with a total molar mass 169.91g?
The compound is silver nitrate (AgNO3). By calculating the molar mass of the compound, which is 169.91 g/mol, we can determine the molecular formula. The molar mass of silver is 107.87 g/mol, nitrogen is 14.01 g/mol, and oxygen is 16.00 g/mol. The molar mass of silver nitrate matches the given value.
What is the molar concentration of 7.25g of silver nitrate dissolved in 100 mL of solution?
First, calculate the molar mass of silver nitrate (AgNO3) = 169.87 g/mol. Next, convert 7.25g to moles by dividing by the molar mass to get 0.0427 mol. Then, calculate the molarity by dividing moles by liters (100 mL = 0.1 L) to get a molarity of 0.427 M.
What is the molar mass of ammonium nitrate?
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
How many molecules are there in 65 g of silver nitrate?
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
How many moles in 1.25 grams of iron nitrate?
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
How mack to 0.1NAgno3?
To make You need the molar mass of Silver nitrate to make 0.1 Silver Nitrate.
Compound made from 63.50 silver 8.25 nitrogen and 28.25 oxygen with a total molar mass 169.91g?
The compound is silver nitrate (AgNO3). By calculating the molar mass of the compound, which is 169.91 g/mol, we can determine the molecular formula. The molar mass of silver is 107.87 g/mol, nitrogen is 14.01 g/mol, and oxygen is 16.00 g/mol. The molar mass of silver nitrate matches the given value.
What is the molar mass of 2AgNO3?
The molar mass of silver nitrate (AgNO3) is approximately 169.87 g/mol. Multiplying this by 2 gives a molar mass of 339.74 g/mol for 2 moles of AgNO3.
How much silver in silver nitrate?
Well, darling, silver nitrate is composed of one silver atom, one nitrogen atom, and three oxygen atoms. So, if you're looking for the amount of silver in silver nitrate, it's simply the atomic weight of silver (107.87 g/mol) multiplied by the molar mass of silver nitrate (169.87 g/mol), which gives you approximately 63.5% silver by weight. But hey, who's counting?
Mass of silver in 3.4g AgNO3?
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
How many moles in 4.50 grams of silver nitrate?
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
What is the molar concentration of 7.25g of silver nitrate dissolved in 100 mL of solution?
First, calculate the molar mass of silver nitrate (AgNO3) = 169.87 g/mol. Next, convert 7.25g to moles by dividing by the molar mass to get 0.0427 mol. Then, calculate the molarity by dividing moles by liters (100 mL = 0.1 L) to get a molarity of 0.427 M.
What is the molar mass of ammonium nitrate?
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
How many molecules are there in 65 g of silver nitrate?
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
What mass of silver chloride can be produced from 1.85 L of a 0.141 M solution of silver nitrate?
First, calculate the moles of silver nitrate in the solution using Molarity = moles/volume. Then, use the balanced chemical equation between silver nitrate and silver chloride to determine the moles of silver chloride that can be produced. Finally, convert the moles of silver chloride to grams using the molar mass of silver chloride.
What is the molar mass for nitrate?
169.8731 g/mol
What mass of silver chloride can be produced from 1.59L of a 0.300M solution of silver nitrate?
To find the mass of silver chloride produced, first calculate the moles of silver nitrate using Molarity = moles/volume. Then, use the mole ratio from the balanced chemical equation to find the moles of silver chloride produced. Finally, multiply the moles of silver chloride by its molar mass to find the mass of silver chloride produced.
