4.50 g(1/169.88) =.0265 mols
1 mole of silver nitrate produces 1 mole of silver when it reacts to completion. Therefore, 7 moles of silver nitrate will produce 7 moles of silver.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
If the reaction is stoichiometric, 1.30 moles of zinc will generate an equal number of moles of silver. This is based on the balanced chemical equation for the reaction between zinc and silver nitrate.
1 mole of silver nitrate produces 1 mole of silver chloride in a 1:1 ratio according to the balanced chemical equation AgNO3 + NaCl -> AgCl + NaNO3. Therefore, 7 moles of silver nitrate will produce 7 moles of silver chloride.
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
1 mole of silver nitrate produces 1 mole of silver when it reacts to completion. Therefore, 7 moles of silver nitrate will produce 7 moles of silver.
There are 0.13 moles in 20 grams of magnesium nitrate.
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
Since silver chromate has a 1:1 molar ratio with silver nitrate, 4 moles of silver nitrate will produce 4 moles of silver chromate.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
If the reaction is stoichiometric, 1.30 moles of zinc will generate an equal number of moles of silver. This is based on the balanced chemical equation for the reaction between zinc and silver nitrate.
To completely replace silver in the solution with copper, you would need an equal number of moles of copper to the moles of silver present. Calculate the moles of silver in the solution using the concentration and volume given. Then use the mole ratio between copper and silver to determine the moles of copper needed, and convert this to grams.
15.451
You need 145,337 g silver nitrate.