13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
How many moles are in 20.0 grams of magnesium nitride
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
how many moles are there in 56.0 grams of silver nitrate?
4.50 g(1/169.88) =.0265 mols
160 grams MgO (1 mole MgO/40.31 grams) = 3.97 mole magnesium oxide =====================
A sample of 56,4 of magnesium is equal to 2,32 moles.
There are 0.13 moles in 20 grams of magnesium nitrate.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
1,11 moles of magnesium have 26,97855 g.
88,1 moles of magnesium is equivalent to 2 141,27 g.
1,25 g of anhydrous iron(III) nitrate = 0,005 moles
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
15.451
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
how many moles are there in 56.0 grams of silver nitrate?
4.50 g(1/169.88) =.0265 mols
Hydrogen nitrate has a mass of 63.01 g/mol. In order to find the number of moles you divide the grams by the molar mass. 250/63.01 = 3.96 mol.