Ca(NO3)2
5.600 grams calcium nitrate ( 1mole Ca(NO3)2/164.1 grams)(2 moles NO3/1 mole Ca(NO3)2)
= 6.825 X 10 -2 moles of nitrate ions
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Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
To find the concentration of nitrate ions in the mixture, we first calculate the moles of nitrate ions from each salt using the formula moles = concentration x volume. For potassium nitrate: 0.120 mol/L x volume = moles of nitrate ions. For iron (II) nitrate: 0.160 mol/L x volume = moles of nitrate ions. Add the moles of nitrate ions from both salts to get the total moles of nitrate ions in the mixture. Finally, divide the total moles of nitrate ions by the total volume of the mixture to get the concentration of nitrate ions in the mixture.
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
Calcium Nitrtae is Ca(NO3)2 and so there are two moles of nitrate per mole of calcium nitrate. Thus there are 2 x 2.50 = 5.0 moles of nitrate present.
To determine how many miles of calcium nitrate would react with 4.55 moles of Chromium (III) sulfate to produce chromium (III) nitrate, you would first need to write the balanced chemical equation for the reaction between calcium nitrate and chromium (III) sulfate. Then, use the stoichiometry of the reaction to convert moles of Chromium (III) sulfate to moles of calcium nitrate, and finally, convert moles of calcium nitrate to miles using the molar mass.
Ca (NO3)2 So the number of Ca atoms will just be Avogadro's constant, L
6,022 x 1023 atoms/mole. Calcium nitrate = Ca(NO3)2 .There are 1 mole of calcium making 6,022 x 1023 atoms of calcium.There are 2 moles of nitrate-ions and each nitrate-ion is made up of 1 mole nitrogen, and 3 moles of oxygen. Thath means that the nitrate ion in calcium nitrate has 6 moles oxygen and 2 moles of nitrate:Atoms of nitrogen: 6,022 x 1023 moles-1 x 2 moles = 1,2044 x 1024 atomsAtoms of oxygen: 6,022 x 1023 moles-1 x 6 moles = 3,6132 x 1024 atoms
The term used to describe the 4 in the expression 4 Ca(NO3)2 is a "coefficient." It indicates the number of moles of the compound calcium nitrate (Ca(NO3)2) present in the chemical equation. In this case, it signifies that there are four moles of calcium nitrate.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
7,68 grams of calcium nitride is equal to 0,052 moles.
When calcium nitrate (Ca(NO₃)₂) reacts with potassium iodide (KI), the balanced chemical equation is: [ \text{Ca(NO}_3\text{)}_2 + 2 \text{KI} \rightarrow \text{CaI}_2 + 2 \text{KNO}_3 ] In this reaction, one mole of calcium nitrate reacts with two moles of potassium iodide to produce one mole of calcium iodide and two moles of potassium nitrate.
No, the moles of silver ions in water depend on the concentration of the silver ions present, while the moles of silver ions in a silver nitrate solution depend on the amount of silver nitrate dissolved. The two may not be equal unless the silver nitrate is completely dissociated into silver ions in water.
To calculate the mass of water in the solution, you first need to find the molar mass of calcium nitrate (Ca(NO3)2), which is 164.1 g/mol. Next, calculate the moles of solute by dividing the mass of the solute by its molar mass. Then, use the molarity and moles of solute to find the moles of water in the solution using the formula: moles of water = moles of solute * 2 (since calcium nitrate has 2 nitrate ions per formula unit). Finally, find the mass of water by multiplying the moles of water by the molar mass of water (18 g/mol).
There are 6 moles of nitrate ions in 2 moles of magnesium nitrate. This is because there are 3 nitrate ions (NO3-) in each formula unit of magnesium nitrate (Mg(NO3)2). So, 2 moles of Mg(NO3)2 would contain 6 moles of nitrate ions.
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.