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How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many elements in magnesium sulfide?
Magnesium sulfide contains two elements: magnesium and sulfur.
How many grams are there in 3.3 moles of potassium sulfide?
The atomic mass of Potassium is 39 and that of Sulfur 32. The formula for Potassium Sulfide is K2S therefore the molecular weight of Potassium Sulfide is (39 * 2) + 32 = 110. Therefore one mole of Potassium Sulfide weighs 110 grams. Therefore 3.3 moles of Potassium Sulfide weigh 110 * 3.3 = 363 grams.
How many grams is 0.348 mol of magnesium?
Molecular mass of magnesium = 24.305 g/mol. 0.478 g/24.305 g/mol = .0197 mols
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many grams are in 1.11 moles of magnesium?
1,11 moles of magnesium have 26,97855 g.
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many moles are in 88.1 grams of magnesium?
88,1 moles of magnesium is equivalent to 2 141,27 g.
How many grams are in 2.2 moles of potassium sulfide?
242.594 g
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams of iron II sulfide have to react with hydrochloric acid to generate 12 g of hydrogen sulfide?
To calculate the grams of iron II sulfide needed, we start by finding the moles of hydrogen sulfide produced. This is done by dividing the given mass of hydrogen sulfide by its molar mass. Then, we use the balanced chemical equation to determine that for every 4 moles of hydrogen sulfide, 1 mole of iron II sulfide is needed. From this, we find the grams of iron II sulfide required by multiplying the moles of iron II sulfide by its molar mass.
How many grams are in 3.3 moles of potassium sulfide K2S?
To find the number of grams in 3.3 moles of potassium sulfide (K2S), you need to calculate the molar mass of K2S, which is 110.26 g/mol. Then, you can multiply the molar mass by the number of moles to get the grams. In this case, 3.3 moles x 110.26 g/mol = 363.858 g.
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
How many elements in magnesium sulfide?
Magnesium sulfide contains two elements: magnesium and sulfur.
How many moles are in 300 grams of calcium sulfide?
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
How many moles are in 13.2 grams of magnesium?
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
How many moles are in 125.00 grams of sodium sulfide?
There are at least three kinds of sodium sulfide, but assuming that the question refers to the most common one with the formula Na2S, its gram formula mass, the mass corresponding to molar mass for covalently bonded compounds, is 78.04. Therefore 125.00 constitutes 125.00/78.04 or 1.6017 "moles".
