There are at least three kinds of sodium sulfide, but assuming that the question refers to the most common one with the formula Na2S, its gram formula mass, the mass corresponding to molar mass for covalently bonded compounds, is 78.04. Therefore 125.00 constitutes 125.00/78.04 or 1.6017 "moles".
125 g H2SO4 is equivalent to 1,274 moles.
Approx. 7 moles.
1.274 moles
1.27 mols
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
.73 moles
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
234 grams :)
1
300 g of calcium sulfide (CaS) is equal to 4,158 moles.
The formula mass of sodium sulfide, Na2S, is 2(23.0)+32.1=78.1 Amount of sodium sulfide = 73.5/78.1 = 0.941mol
The formula of sodium sulfide is Na2S, where the 2 should be a subscript. It means that in the ionic compound there are 2 moles of sodium ions for every 1 mole of sulfide ions.
The formula of sodium sulfide is Na2S, where the 2 should be a subscript. It means that in the ionic compound there are 2 moles of sodium ions for every 1 mole of sulfide ions.
23.3772 grams are there in four tenths moles of sodium chloride
242.594 g
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
.73 moles
55.0 moles of sodium are equal to 1 264,44 g.
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
Quite a few! 5.13 kilograms sodium (1000 grams/1 kg)(1 mole Na/22.99 grams) = 223 moles of sodium =================