There are at least three kinds of sodium sulfide, but assuming that the question refers to the most common one with the formula Na2S, its gram formula mass, the mass corresponding to molar mass for covalently bonded compounds, is 78.04. Therefore 125.00 constitutes 125.00/78.04 or 1.6017 "moles".
To calculate the grams of iron II sulfide needed, we start by finding the moles of hydrogen sulfide produced. This is done by dividing the given mass of hydrogen sulfide by its molar mass. Then, we use the balanced chemical equation to determine that for every 4 moles of hydrogen sulfide, 1 mole of iron II sulfide is needed. From this, we find the grams of iron II sulfide required by multiplying the moles of iron II sulfide by its molar mass.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
To calculate the mass of 4.00 moles of sodium, you can use the molar mass of sodium which is approximately 23 grams/mol. Therefore, 4.00 moles of sodium would have a mass of 4.00 moles * 23 grams/mole = 92 grams.
To make a 2 molal solution, you would need 2 moles of lithium sulfide per 1000g of water. Since you have 1600g of water, you need 2 x (1600 / 1000) = 3.2 moles of lithium sulfide. To find the grams needed, you would multiply the molar mass of lithium sulfide (45.94 + 32.06) by the number of moles needed (3.2) to get 149.12 grams.
62 grams a+
To determine the number of moles in 73.5 g of sodium sulfide (Na2S), you first need to calculate the molar mass of Na2S, which is 78.04 g/mol. Then divide the given mass by the molar mass to find the number of moles. Therefore, 73.5 g / 78.04 g/mol = 0.942 moles of sodium sulfide.
23.3772 grams are there in four tenths moles of sodium chloride
To calculate the grams of iron II sulfide needed, we start by finding the moles of hydrogen sulfide produced. This is done by dividing the given mass of hydrogen sulfide by its molar mass. Then, we use the balanced chemical equation to determine that for every 4 moles of hydrogen sulfide, 1 mole of iron II sulfide is needed. From this, we find the grams of iron II sulfide required by multiplying the moles of iron II sulfide by its molar mass.
The formula of sodium sulfide is Na2S, where the 2 should be a subscript. It means that in the ionic compound there are 2 moles of sodium ions for every 1 mole of sulfide ions.
To find the number of moles in 45.5 g of sodium sulfide (Na2S), first calculate the molar mass of Na2S which is 78.045 g/mol. Then, divide the given mass by the molar mass to get the number of moles. Therefore, there are 0.583 moles of sodium sulfide in 45.5 g.
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
3 x 2 x 23 = 138g
The formula of sodium sulfide, Na2S, indicates that each sodium sulfide molecule contains two sodium (Na) ions and one sulfide (S) ion. The ratio of sodium ions to sulfide ions in sodium sulfide is 2:1.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
242.594 g
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.