0
What else can I help you with?
What is the mass percent concentration of the solution prepared by adding 20 g of sodium chloride into 380 g of water?
Divide the amount of sodium chloride by the total amount (sodium chloride + water). Then multiply that by 100 to convert to percent.
The sterile solution used to rinse contact lenses can be made by dissolving 400 mg of NaCl in sterile water and diluting to 100 mL. what is the molarity of this solution?
To calculate the molarity of the solution, we first need to determine the number of moles of NaCl in 400 mg. The molar mass of NaCl is approximately 58.44 g/mol. Converting 400 mg to grams gives us 0.4 g. Dividing this by the molar mass gives us approximately 0.0068 moles of NaCl. Since the volume is 100 mL or 0.1 L, the molarity is calculated as moles divided by liters, giving us approximately 0.068 M.
How many grams of sodium fluoride are needed to prepare a 0.400m NaF solution that contains 750g of water?
To prepare a 0.400m NaF solution, you need to dissolve 0.400 moles of NaF per liter of solution. With 750g of water, you have about 0.416 L of water. To calculate the grams of NaF needed, multiply the molarity by the volume of solution in liters, then multiply by the molar mass of NaF (sodium fluoride: 41.99 g/mol). So, you would need about 6.991 grams of NaF.
How would you prepare 400ml of a 0.24M NaCl solution?
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
How many mole of chlorine ions are in 400 g of AlCl3?
In one mole of AlCl3, there are 3 moles of chloride ions. The molar mass of AlCl3 is 133.34 g/mol. Therefore, there are 6.022 x 10^23 chloride ions in 133.34 g of AlCl3. To find the number of chloride ions in 400 g of AlCl3, you would calculate (6.022 x 10^23) x (400 g / 133.34 g/mol) = approximately 1.8 x 10^24 chloride ions.
How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
How many moles of sodium chloride are in 400 mL of a 6 M NaCl solution?
The answer is 2,4 moles.
What mass of O2 will react with 400 g of C4 H10?
To find the mass of O2 that will react with 400 g of C4H10, first calculate the moles of C4H10 using its molar mass. Then, using the balanced chemical equation for the reaction between C4H10 and O2, determine the mole ratio between C4H10 and O2. Finally, convert the moles of C4H10 to moles of O2 and then to grams of O2 using the molar mass of O2.
How many mg in 2 g?
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
What is the mass percent concentration of the solution prepared by adding 20 g of sodium chloride into 380 g of water?
Divide the amount of sodium chloride by the total amount (sodium chloride + water). Then multiply that by 100 to convert to percent.
How do you calculate the number of moles of NaI in 50.0mL of a 0.400M solution?
To calculate the number of moles of NaI in 50.0mL of a 0.400M solution, you first need to convert the volume to liters by dividing by 1000 (since 1L = 1000mL). Then, use the formula moles = Molarity x Volume (in liters) to find the number of moles of NaI. In this case, it would be 0.400 mol/L x 0.050 L = 0.020 moles of NaI.
How many moles are in 400 grams of nickel sulphate?
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
What is 400 subtracted from 2000?
-1600
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
The sterile solution used to rinse contact lenses can be made by dissolving 400 mg of NaCl in sterile water and diluting to 100 mL. what is the molarity of this solution?
To calculate the molarity of the solution, we first need to determine the number of moles of NaCl in 400 mg. The molar mass of NaCl is approximately 58.44 g/mol. Converting 400 mg to grams gives us 0.4 g. Dividing this by the molar mass gives us approximately 0.0068 moles of NaCl. Since the volume is 100 mL or 0.1 L, the molarity is calculated as moles divided by liters, giving us approximately 0.068 M.
Suppose you have 20.8 g of Cr What number of moles of Cr is present?
.400 moles
What is the number of moles of solute in 400 ml of a 0.4 M solute?
The answer is 0,16 moles.
