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How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
What is molecular mass of Magnesium in Magnesium Chloride?
The molecular mass of magnesium in magnesium chloride is 24.305 grams/mol.
What is the molarity of a solution made with 128 grams of magnesium chloride dissolved in one liter of water?
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
What is the mass of 0.3 moles of magnesium sulfate?
The molar mass of magnesium sulfate (MgSO₄) is approximately 120.37 g/mol. To find the mass of 0.3 moles, you multiply the number of moles by the molar mass: 0.3 moles × 120.37 g/mol = 36.11 grams. Therefore, the mass of 0.3 moles of magnesium sulfate is about 36.11 grams.
How many grams of co2 are in 2l mol of the compound?
92.4 grams
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?
To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.
What is molecular mass of Magnesium in Magnesium Chloride?
The molecular mass of magnesium in magnesium chloride is 24.305 grams/mol.
In the reaction between magnesium and oxygen the mass of magnesium and oxygen was 2.5 grams how much magnesium oxide was formed?
The molar mass of magnesium is 24.3 g/mol and oxygen is 16 g/mol. The balanced equation is 2Mg + O2 -> 2MgO. Since magnesium and oxygen react in a 1:1 ratio, all magnesium reacted to form magnesium oxide. Therefore, 2.5 grams of magnesium oxide was formed.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many moles are in 13.2 grams of magnesium?
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
What is the molarity of a solution made with 128 grams of magnesium chloride dissolved in one liter of water?
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
Can you calculate the number of moles of magnesium used grams permol?
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
Is magnesium lighter than gold?
Yes. the molecular weight of magnesium is 24.3 g/mol and gold is 197
Calculate the Mass of magnesium sulphate that would be obtained from 4 grams of magnesium?
Masses: Mg= 24, S= 32, O= 16 Magnesium = 24g Magnesium sulphate = (24+32)+(16x4) = 120g. Therefor we know: 24g of Mg ----> makes 120g of MgSO4. To get to 4g from 24g, you devide by 6. (24 devided by 6 = 4g) And to find what it would make, you devide 120 by 6 too. Which = 20g. 4g of Mg ----> 20g of MgSO4.
