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What is the molarity of chloride ion in 100 ml of a 500 M barium chloride solution?
I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.
What else can I help you with?
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
What mass of barium sulfate can be produced when 100.00 ml of a 100 M solution of barium chloride is mixed with 100.0 ml of a 100 M solution of iron III sulfate?
To find the mass of barium sulfate produced, first calculate the moles of barium chloride and iron III sulfate using their volumes and concentrations. Then, determine the limiting reactant by comparing the moles of barium chloride and iron III sulfate and use it to find the moles of barium sulfate produced. Finally, multiply the moles of barium sulfate by its molar mass to find the mass in grams.
A solution contains 11 by mass of sodium chloride This means that?
100 g of the solution contains 11 g of sodium chloride
How do you calculate the percent chloride with the volhard method?
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide KI in 100 mL of water?
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
What mass of barium sulfate can be produced when 100.00 ml of a 100 M solution of barium chloride is mixed with 100.0 ml of a 100 M solution of iron III sulfate?
To find the mass of barium sulfate produced, first calculate the moles of barium chloride and iron III sulfate using their volumes and concentrations. Then, determine the limiting reactant by comparing the moles of barium chloride and iron III sulfate and use it to find the moles of barium sulfate produced. Finally, multiply the moles of barium sulfate by its molar mass to find the mass in grams.
At what temperature barium chloride conert to anhydrous from hydrate stage?
From 100 to 113 Deg C, barium chloride convert to anhydrous form.
Which is Sparingly soluble- barium chloride or barium sulfate?
Barium sulfate is sparingly soluble in water, while barium chloride is more soluble. Barium sulfate has a solubility of about 0.0015 g/100 mL of water at room temperature, while barium chloride is much more soluble at about 36 g/100 mL of water at room temperature.
How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
A solution contains 11 by mass of sodium chloride This means that?
100 g of the solution contains 11 g of sodium chloride
What is the molarity of 1.97 mole of LiCl in 33.2 liter of solution?
You know because of solubility rules that LiCl disassociates 100% in water. So, knowing that molarity is equal to moles/liters Molarity LiCl = 1.97mol / 33.2 L Molarity = 0.059 M LiCl
What is the molarity of 15 g NaOH in a 100 L aqueous solution?
To determine the molarity of 15 g NaOH in a 100 L solution, first calculate the moles of NaOH using its molar mass (40 g/mol). Then, divide the moles by the volume in liters (100 L) to get the molarity. The molarity of the NaOH solution would be 0.375 M.
What is the osmolarity of a 0.1 mole sodium chloride solution?
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
How do you calculate the percent chloride with the volhard method?
To calculate the percent chloride using the Volhard method, you measure the excess silver nitrate used to titrate the chloride ions in the sample. You then use the volume of excess silver nitrate and the molarity of the silver nitrate solution to calculate the moles of chloride present. Finally, calculate the percent chloride by dividing the moles of chloride by the sample weight and multiplying by 100.
What is a procedure for making 100 ml of a 0.10 M solution of barium nitrate?
Ba(NO3)2 Molarity = moles of solute/Liters of solution ( 100 ml = 0.100 liters ) 0.10 M Ba(NO3)2 = moles Ba(NO3)2/0.100 liters = 0.01 moles Ba(NO3)2 (261.32 grams/1 mole Ba(NO3)2) = 2.6 grams of Ba(NO3)2 needs to be put into that 100 milliliters of solution.
What is the molarity of a solution made by dissolving 3.09 moles of Nacl in 1.50 L of solution?
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
