15g in 100L is 0.15g/ litre. The molecular weight of NaOH is 40g/mol. 0.15/40 is .00375 molar.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
First, calculate the number of moles of NaOH using its molar mass (40 g/mol). Then, calculate the molarity using the formula Molarity = moles of solute / volume of solution in liters. In this case, the molarity would be calculated in moles per liter, so you would need to convert the volume of 100 ml to liters (0.1 L) before you divide.
The molarity of a sodium hydroxide solution with a molecular weight of 40g containing 20g in 100ml of solution can be calculated as follows: Moles of NaOH = Mass of NaOH / Molecular weight of NaOH = 20g / 40g/mol = 0.5 moles Molarity = Moles of solute / Volume of solution in liters = 0.5 moles / 0.1 L = 5 M Therefore, the normality of this solution would be 5 N as normality is equal to molarity multiplied by the number of equivalents per mole of solute for sodium hydroxide, which is 1.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
To calculate the grams of NaOH needed, use the formula: mass (g) = molarity (M) x volume (L) x molar mass (g/mol). First, convert 100 ml to liters by dividing by 1000. Then, plug in the values for molarity (0.2 M), volume (0.1 L), and molar mass of NaOH (40 g/mol) to find the answer: mass (g) = 0.2 x 0.1 x 40 = 0.8 grams of NaOH.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
The molarity of the solution is calculated by dividing the moles of solute by the volume of solution in liters. First, convert the volume from milliliters to liters (353 mL = 0.353 L). Then, divide the moles of NaOH (0.73 mol) by the volume of the solution in liters (0.353 L) to get the molarity. Molarity = 0.73 mol / 0.353 L ≈ 2.07 M.
I think it'd be pH 7. Same amount of both, providing they are the same molarity!
First, calculate the number of moles of NaOH using its molar mass (40 g/mol). Then, calculate the molarity using the formula Molarity = moles of solute / volume of solution in liters. In this case, the molarity would be calculated in moles per liter, so you would need to convert the volume of 100 ml to liters (0.1 L) before you divide.
The molarity of a sodium hydroxide solution with a molecular weight of 40g containing 20g in 100ml of solution can be calculated as follows: Moles of NaOH = Mass of NaOH / Molecular weight of NaOH = 20g / 40g/mol = 0.5 moles Molarity = Moles of solute / Volume of solution in liters = 0.5 moles / 0.1 L = 5 M Therefore, the normality of this solution would be 5 N as normality is equal to molarity multiplied by the number of equivalents per mole of solute for sodium hydroxide, which is 1.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
To calculate the grams of NaOH needed, use the formula: mass (g) = molarity (M) x volume (L) x molar mass (g/mol). First, convert 100 ml to liters by dividing by 1000. Then, plug in the values for molarity (0.2 M), volume (0.1 L), and molar mass of NaOH (40 g/mol) to find the answer: mass (g) = 0.2 x 0.1 x 40 = 0.8 grams of NaOH.
Yes, you can make a 1N NaOH solution from a 0.1N NaOH solution by diluting it 10 times. For example, to make 1 liter of 1N NaOH solution, you would mix 100 ml of the 0.1N NaOH solution with 900 ml of water.
Strong acid with strong base always ends with neutral water and the resulting ions Na+ and Cl-, both neutral as well!
Well, honey, preparing a 5 N NaOH solution is as easy as pie. Just measure out the appropriate amount of NaOH pellets and dissolve them in water until you reach the desired volume. Make sure to wear your safety goggles and gloves, because nobody wants a chemical burn. And voilà, you've got yourself a 5 N NaOH solution ready to go.
To make a 10% NaOH solution, you would need 100 grams of NaOH per liter of water. So to make 1 liter, you would need 100 grams of NaOH.
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To prepare a 0.10 M solution in 100 mL, you would need 1.0 g of NaOH. This can be calculated using the formula: mass (g) = molarity (M) x volume (L) x molar mass (g/mol).