40 g NaOH in 1 liter is 1 molar. So 400 mg = 0.4 g in 100 ml = 4 g per liter and thus 0.1 molar.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
The molarity of sweet tea depends on the amount of solute (sugar) dissolved in the solution. If you know the amount of sugar added to a specific volume of tea, you can calculate the molarity using the formula: Molarity (M) = moles of solute / liters of solution.
By adding 65.9 mL of water to the 2.39 M solution of HCl, the final volume becomes 469.9 mL. To find the final molarity, we use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, and M2 and V2 are the final molarity and volume, respectively. Substituting the values, we can calculate the final molarity of the diluted solution.
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There isn't enough to answer your question. You've given a volume, but haven't given a weight or amount of moles. I also do not know if there is a relevance to your including the graduated cylinder. A solution should always be made up in a volumetric flask.
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
the answer is 100ml the answer is 100ml
To prepare a 2% solution of ferric chloride in 100ml of water, you would need to add 2 grams of ferric chloride. This is calculated by multiplying the volume of the solution (100ml) by the desired concentration (2%) and converting it to grams.
Because the concentrations of solutes are lowered.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
If you want to convert that to liters, divide the number by 1000.
Pure water does not have a molarity because it is not a solute dissolved in a solvent. However, under standard conditions, the molarity of pure water is 55.56 mol/L, which corresponds to its concentration of water molecules.
The molarity of sweet tea depends on the amount of solute (sugar) dissolved in the solution. If you know the amount of sugar added to a specific volume of tea, you can calculate the molarity using the formula: Molarity (M) = moles of solute / liters of solution.
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.