1.17 grams :)
how will you prepare 0.38M sodium acetate solution
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
Dissolve 30g of sodium chloride in 100 mL of water.
100ml is 0.1 litres, so you need 0.1 moles of sodium chloride.
I suppose that this solution doesn't exist.
how will you prepare 0.38M sodium acetate solution
A sodium solution of water cannot be made as sodium reacts violently with water to produce sodium hydroxide.
Sodium chloride is used to prepare the 0,9 % isotonic solution.
Sodium chloride may be used as standard (for example to prepare sodium solutions with known concentration) because is a stable compound.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
To prepare a buffer solution which may be acidic. Titrate ethanoic acid (weak acid) with sodium ethanoate(salt).
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
By a slowly evaporation of water from a NaCl solution.
In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.
i think it is one third of the hypochlorite solution and remaining normal saline
Sodium chloride is needed to precipitate soap from solutions.
impossible....u want to use a low contrated solution to dilute into a higher contration solution? No way man,...