Step 1: Write the balanced "molecular" equation:
2 HI + Ba(OH)2 BaI2 + 2H2O
Step 2: Consult the solubility rules linked above to determine whether each substance will dissociate:
2 HI+
Ba(OH)2
BaI2+2 H2O
yes
yes
yes
Step 3: Dissociate all soluble salts, strong acids, and strong bases (except calcium hydroxide). Leave together all "not soluble" salts and weak acids or bases. Note that when H3O+ loses a proton, a water molecule is formed.
2H3O+ (aq) + 2I- (aq) + Ba2+ (aq) + 2OH- (aq)Ba2+ (aq) + 2I- (aq) + 4 H2O (l)
Step 4: Cross out "spectator ions" that appear on both sides of the reaction (these ions do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients.
H3O+ (aq) + OH- (aq) 2 H2O (l)
Barium hydroxide is an ionic compound because it is composed of a metal (barium) and a non-metal (hydroxide ion). Ionic compounds are formed by the transfer of electrons from the metal to the non-metal.
The balanced chemical equation for the reaction between barium nitrate and sodium hydroxide is: Ba(NO₃)₂ + 2NaOH → Ba(OH)₂ + 2NaNO₃
The net ionic equation for the reaction between sodium acetate (NaCH₃COO) and barium hydroxide (Ba(OH)₂) is: CH₃COO⁻(aq) + Ba²⁺(aq) → Ba(CH₃COO)₂(s) Sodium ions and hydroxide ions do not participate in the formation of the precipitation of barium acetate, so they are not included in the net ionic equation.
The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.
The net ionic equation for barium hydroxide (Ba(OH)2) plus hydrobromic acid (HBr) is Ba(OH)2 + 2H+ + 2Br- -> Ba2+ + 2Br- + 2H2O. This equation highlights the formation of barium ions (Ba2+) and water molecules (H2O) as the only significant species in the reaction.
Barium hydroxide is a molecular compound.
Barium hydroxide is an ionic compound because it is composed of a metal (barium) and a non-metal (hydroxide ion). Ionic compounds are formed by the transfer of electrons from the metal to the non-metal.
Ba is Barium, OH is Hydroxide and the 8 H2O is Octahydrate. This results in Barium Hydroxide Octahydrate.
Barium hydroxide is not a cation or an anion. It is a compound. It is made of barium ions and hydroxide ions.
Barium hydroxide
The balanced chemical equation for the reaction between barium nitrate and sodium hydroxide is: Ba(NO₃)₂ + 2NaOH → Ba(OH)₂ + 2NaNO₃
The equation is , Ba(OH)2 + 2HCl = BaCl2 + 2H2O
Ba(OH)2 is an ionic compound. Barium hydroxide dissociates in water to form barium ions (Ba2+) and hydroxide ions (OH-), which are held together by ionic bonds.
The net ionic equation for the reaction between sodium acetate (NaCH₃COO) and barium hydroxide (Ba(OH)₂) is: CH₃COO⁻(aq) + Ba²⁺(aq) → Ba(CH₃COO)₂(s) Sodium ions and hydroxide ions do not participate in the formation of the precipitation of barium acetate, so they are not included in the net ionic equation.
No, barium hydroxide is soluble in water. When dissolved in water, it dissociates into barium ions (Ba²⁺) and hydroxide ions (OH⁻).
The precipitate formed when barium chloride reacts with sodium hydroxide is barium hydroxide (Ba(OH)2).
The molecular equation for the reaction between copper (II) sulfate and barium chloride is: CuSO4 + BaCl2 -> BaSO4 + CuCl2. In this reaction, the copper (II) ions switch places with the barium ions to form barium sulfate and copper (II) chloride.