ethyl is C2H5 and propyl is C3H7 and cyclobutane is C4H8 so removing two hydrogens that will be replaced by the ethyl and propyl leaves (C2H5)(C3H7)C4H6 which leaves a net C9H18
What is the molecular formula of 2-Butyne
The molecular formula for chromous hydroxide is Cr(OH)2. In this compound, chromium has a +2 oxidation state and forms a compound with hydroxide ions.
To find the molecular formula from the empirical formula (C2H5), we need to know the molecular mass of the compound. Since the formula implies a molecular mass of 29 g/mol (12 g/mol for carbon and 1 g/mol for hydrogen), if we divide the molecular mass of the compound by the empirical formula mass (C2H5 = 212 + 51 = 29 g/mol), we find that the molecular formula is the same as the empirical formula, C2H5.
The answer is coded in the question itself: "Di" means 2 and "pent" means five; therefore the formula is P2O5.
Ch3ch3cclch3
What is the molecular formula of 2-Butyne
Ch2(cho)2 is the molecular formula for malondialdehyde.
To determine the molecular formula from the empirical formula CH2O and given molecular mass of 60.0 amu, calculate the empirical formula mass: (12.01 g/mol for C) + 2(1.01 g/mol for H) + 16.00 g/mol for O = 30.02 g/mol. Then divide the given molecular mass by the empirical formula mass to find the factor by which the empirical formula must be multiplied to get the molecular formula: 60.0 amu / 30.02 g/mol ≈ 2. Next, multiply the subscripts in the empirical formula by this factor to find the molecular formula: 2(C)2(H)2(O) = C4H4O2, giving the molecular formula as C4H4O2.
The molecular formula for 2-methyl-1-propanol is C4H10O.
The empirical formula of C2H5 corresponds to an empirical mass of 29 g/mol. To find the molecular formula from the empirical formula and molecular mass, divide the molecular mass by the empirical mass to get the "scaling factor" (58 g/mol ÷ 29 g/mol = 2). Multiply the subscripts in the empirical formula by the scaling factor to get the molecular formula: C2H5 x 2 = C4H10. So, the molecular formula is C4H10.
The empirical formula C2H3 has a molecular mass of 27 (C: 12, H: 1). To determine the molecular formula with a molecular mass of 54, the molecular formula would simply be double the empirical formula, so the molecular formula would be C4H6.
alkanes
Ascorbic acid is (5R)-[(1S)-1,2-dihydroxyethyl]-3,4-dihydroxyfuran-2(5H)-one. Its molecular formula is C6H8O6
2-nonyne
To find the molecular formula from the empirical formula, we need to know the molar mass of the empirical formula. In this case, the empirical formula's molar mass is 88. To find the molecular formula, we divide the given molecular mass (176) by the empirical formula's molar mass (88) to get 2. This means the molecular formula of Vitamin C is twice the empirical formula, so the molecular formula is C6H8O6.
The molecular formula for ammonical silver nitrate is AgNO3(NH3)2.
Empirical formula = C3H5O Molar mass of empirical formula = 3(12.01)+5(1.008)+1(16) = 57.07 Molar mass of molecular fomula = 114.15 n = Molar mass of molecular fomula/Molar mass of empirical formula = 114.15/57.07 n = 2 Molecular formula = n(empirical formula) Molecular formula = 2(C3H5O) = C6H10O2 Check: 6(12.01)+10(1.008)+2(16)= 114.14