Potassium sulfate = K2SO4
[2K+]tribunated + 2I-(aq) + Cu2+(aq) + [SO42-]tribunated --> --> CuI2(s) + [2K+ + SO42- ]tribunated
Potassium Hydroxide(KOH) is a base (it is "basic"). An acid will neutralize a base. Acetic acid can be used to neutralize KOH. Baking soda is a base, so it will not work to neutralize KOH.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
If is K2O (potassium oxide) it would be: K2O+H2SO4=K2SO4+H2O It could also form potassium bisulfate: K2O + 2 H2SO4 = 2 KHSO4 + H2O But I'm not sure if you are referring to potassium peroxide (K2O2) or superoxide (KO2)
The salt formed by the reaction of calcium hydroxide and sulfuric acid is calcium sulfate. The formula of this salt is CaSO4. Calcium sulfate is a white in appearance when pure.
The chemical formula of the salt produced is K2SO4, which is potassium sulfate. When potassium hydroxide (KOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction, potassium sulfate is formed along with water.
The products of a neutralization reaction between sulfuric acid and potassium hydroxide are potassium sulfate and water. The balanced chemical equation for this reaction is H2SO4 + 2KOH -> K2SO4 + 2H2O.
Actually there are two possibillities:K2SO4, potassium sulfate, when 1 mole sulfuric acid is added to 2 moles potassium hydroxide 2 KOH + H2SO4 ------> K2SO4 + 2 H2OorKHSO4, potassium hydrogen sulfate (-bisulfate), when 1 mole sulfuric acid is added to 1 mole potassium hydroxide 1 KOH + H2SO4 ------> KHSO4 + H2O
When potassium hydroxide and sulfuric acid react, they undergo a neutralization reaction to form potassium sulfate and water. This reaction involves the exchange of ions between the two compounds, resulting in the formation of the salt potassium sulfate and water as a byproduct.
When potassium hydroxide solution reacts with sulfuric acid, a neutralization reaction occurs. The potassium ion from potassium hydroxide combines with the sulfate ion from sulfuric acid to form potassium sulfate, along with water as a byproduct. The overall reaction can be represented by the equation: 2KOH + H2SO4 → K2SO4 + 2H2O.
The neutralization of sulfuric acid (H2SO4) by potassium hydroxide (KOH) forms potassium sulfate (K2SO4) and water (H2O). This reaction involves the exchange of ions from the acid and base to form a salt and water.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
Potassium displaces the hydrogen in sulfuric acid when reacting with potassium hydroxide to form potassium sulfate and water.
The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to produce potassium sulfate and water is: H2SO4 + 2KOH → K2SO4 + 2H2O
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
Na2SO3(aq) and H2O(l)
Water is formed by the combination of H+ ions from sulfuric acid and OH- ions from potassium hydroxide to produce H2O molecules. This reaction is a typical acid-base neutralization reaction where the acid and base react to form water and a salt.