C14 H 28 has 14 carbon atoms and 28 hydrogen atoms it is not an alkane though it is an alkene because the formula for alkanes is Cn H2n+2 whereas alkenes have the formula Cn H2n so if you apply the 14 carbon atoms to the first part of the equation so C14 then the amount of hydrogen atoms has to be two times that amount and what is 14 times 2? 28! So it must be an alkene!
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
C4H8 can refer to either an alkene or an alkane. In the case of an alkene, it would be 1-butene, while for an alkane, it would be 2-methylpropene. The distinction can be made based on the presence of a double bond in the alkene.
If the C4H8 compound is butene-1 or -2 or 2-methylpropene, the product is one of the chlorobutanes with general formula C4H9Cl. If the C4H8 compound is cyclobutane, there is no reaction at standard temperature and pressure.
The alkene will have 8 hydrogen atoms. It's chemical formula would be C4H8.
This question is ambiguous, because double bonds do not occur "in" a particular carbon atom but between 2 carbon atoms. If the chain is straight and the double bond occurs between the second and third atoms counting from one end of the chain, the name of the compound is butene-2, 2-butene, or but-2-ene. If the double bond occurs between the third and fourth atoms counting from one end of the chain,the name of the compound is butene-1, 1-butene, or but-1-ene. (Numbers in a hydrocarbon chain are selected so as to use the smaller number consistent with actual structure, irrespective of the end from which the counting is started.)
C4H8 can be classified as an alkene, specifically as butene, which is an unsaturated hydrocarbon with a carbon-carbon double bond.
The chemical equation for the combustion of butene (C4H8) is: C4H8 6O2 - 4CO2 4H2O This equation shows that butene reacts with oxygen to produce carbon dioxide and water.
When it burns completely, each molecule of C4H8 becomes 4 molecules of CO2 and 4 molecules of H2O.
C4H8 has a square planar shape. It consists of a central carbon atom bonded to two other carbon atoms and two hydrogen atoms.
CCl4 is carbon tetrachloride, with one carbon atom and four chlorine atoms, while C4H8 is butene, with four carbon atoms and eight hydrogen atoms. Butene is an alkene, while carbon tetrachloride is a non-polar solvent commonly used in organic chemistry.
C4H8 can refer to two different organic compounds: butene and butane. Butene is a linear alkene with four carbon atoms, while butane is a straight-chain alkane. So, C4H8 can be both butane and butene, depending on the specific structure.
Empirical formula (lowest whole number) for C4H8 is CH2, obtained by dividing by 4.
C4H8 can refer to either an alkene or an alkane. In the case of an alkene, it would be 1-butene, while for an alkane, it would be 2-methylpropene. The distinction can be made based on the presence of a double bond in the alkene.
C4H8 can refer to several structural isomers, one of which is 1,2-butadiene, commonly known as an allene. However, not all C4H8 compounds are allenes; for example, it can also represent cyclobutane or 2-butene, which are not allenes. An allene specifically contains a central carbon atom double-bonded to two other carbon atoms, leading to a unique linear arrangement of double bonds. Therefore, C4H8 is not exclusively an allene, but it can include an isomer that is.
the answers is 6 _apex
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
If the C4H8 compound is butene-1 or -2 or 2-methylpropene, the product is one of the chlorobutanes with general formula C4H9Cl. If the C4H8 compound is cyclobutane, there is no reaction at standard temperature and pressure.