Sodium Nitride
The most common compound formed by sodium and nitrogen is sodium nitride, with the formula Na3N. Another possible compound is sodium azide, with the formula NaN3.
The formula is K3N. The name of the compound is potassium nitride.
Using the balanced chemical equation for the decomposition of sodium azide, 2NaN3 -> 2Na + 3N2, we can see that 2 moles of Na3N produce 3 moles of N2. Therefore, for 2.88 mol of NaN3, we would produce 2.88 mol * (3 mol N2 / 2 mol NaN3) = 4.32 moles of N2.
Tetranitrogen tetraselenide is the name of the compound.
The name of the compound Cl2O3 is dichlorine trioxide.
NaN3 (sodium azide) is an ionic compound. It is composed of sodium cations (Na+) and azide anions (N3-) which are held together by ionic bonds due to the transfer of electrons from sodium to azide.
The most common compound formed by sodium and nitrogen is sodium nitride, with the formula Na3N. Another possible compound is sodium azide, with the formula NaN3.
The empirical formula for sodium azide is NaN3.
The formula is K3N. The name of the compound is potassium nitride.
NaN3
To calculate the total number of moles in the 52.0 gram sample of NaN3, divide the given mass by the molar mass of NaN3. First, determine the molar mass of NaN3 by summing the atomic masses of its elements (sodium, nitrogen, and three times the atomic mass of nitrogen). Then, divide the mass of the sample by the molar mass of NaN3 to find the number of moles.
NaN3 decomposed to form nitrogen gas (N2) and sodium. 2NaN3 --> 2Na + 3N2
Sodium azide is a chemical compound with the formula NaN₃. It is commonly used as a preservative and a bacteriostatic agent in laboratory settings. However, it is highly toxic and can release toxic fumes when in contact with certain metals.
Callod sodium acid ( NaN3 )
There is no such substance as NaN3. There is, however, Na3N, which is the ionic compound sodium nitride. Decomposing this compound would probably take a considerable amount of energy, but provided you could do it, the correctly balanced formula would be 2Na3N-->6Na+N2. One mole of anything contains 6.02x1023 representative particles. 253 million is 2.53x108. That amounts to 4.20x10-16 moles (a tiny amount!) The mole ratio of nitrogen product to sodium nitride reactant is 1 to 2, so double that amount to get 8.40x10-16. Still a tiny amount, but it's the answer. This is a good problem to illustrate just how small a sample of something can still contain many millions of particles.
The name of this compound is iodine heptafluoride.
9.28 g