The two will react to form salt and water
HCOOH (aq)+ KOH(aq) --> HCOOK(aq) + H2O(l)
In ionic form,
HCOOH + K+ + OH- --> HCOO- + K+ + H2O
HCOOH is weak acid so it should not be written in ionic form.
K+ ions cancel out leaving
HCOOH + OH- --> HCOO- + H2O (net ionic equation)
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
2H3O+(aq) + Ca(OH)2(s) -> 4H2O(l) + Ca2+(aq)
A hydroxide refers to the OH- polyatomic ion and is formed when an oxygen makes a covalent bond with one hydrogen (however you would not see such ions free in nature as they would more probably be in compounds). Potassium hydroxide (KOH) is formed when Potassium forms ionic bonds with OH- ions while Potassium Oxide (K2O) is formed when potassium forms ionic bonds with the Oxide (O2-) ions. Hydrochloric acid + Potassium Hydroxide ---> Potassium Chloride + Water i.e. HCl(aq) + KOH (aq) ----> KCl (aq) + H2O (l) This reaction is a neutralization reaction and occurs when an acid (HCl) reacts with a base (KOH).
The eqnet ionic equation is HCN + OH- --> H2O + CN-
The reaction between ammonium sulfate (NH4)2SO4 and potassium hydroxide (KOH) produces ammonium hydroxide (NH4OH) and potassium sulfate (K2SO4). The balanced equation is: (NH4)2SO4 + 2KOH → 2NH4OH + K2SO4
The balanced chemical equation for the reaction between perchloric acid (HClO4) and potassium hydroxide (KOH) to form water (H2O) and potassium perchlorate (KClO4) is: HClO4 + KOH → H2O + KClO4
The chemical equation for perchloric acid (HClO4) reacting with aqueous rubidium hydroxide (RbOH) is HClO4 + 2RbOH → RbClO4 + 2H2O. In this reaction, perchloric acid reacts with rubidium hydroxide to form rubidium perchlorate and water.
Potassium oxide(K2O) + water(H2O) --> potassium hydroxide(2KOH)
Potassium plus Water gives Potassium Hydroxide plus Hydrogen
potassium hydroxide is POH and nitric acid is HNO3
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
Perchloric acid is a strong acid. Sodium hydroxide is a strong base. HClO4(aq) + NaOH(aq) ---> Na+(aq) + ClO4-(aq) + H2O(l) This is a balanced chmical reaction since the products and reacts have a 1:1 ratio.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O
The reaction between potassium hydroxide (KOH) and perchloric acid (HClO4) produces potassium perchlorate (KClO4) and water (H2O).
The reaction between ammonium carbonate [(NH4)2CO3] and potassium hydroxide (KOH) will form ammonium hydroxide (NH4OH) and potassium carbonate (K2CO3). The balanced equation is: (NH4)2CO3 + 2KOH → 2NH4OH + K2CO3.
The reaction between potassium hydrogen phthalate (KHP) and sodium hydroxide (NaOH) is a neutralization reaction. The balanced chemical equation for this reaction is: KHP + NaOH -> KNaP + H2O. In this reaction, the potassium hydrogen phthalate reacts with sodium hydroxide to form potassium sodium phthalate and water.
2H3O+(aq) + Ca(OH)2(s) -> 4H2O(l) + Ca2+(aq)