by assuming oxalate ion. Oxalate is reducing agent and consist of2 carbon and 4oxygen , Oxygen has oxidation No:-2 and in Oxalate it becomes 4*-2=-8
and carbon has oxidation No:+3 also 2 carbon present in the oxalate ion therefor equal to =+6.
C2O4 -2
+3*2-2*4=-2
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
C2O4 has a charge of -2
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.
In Mg2P2O7, magnesium (Mg) has an oxidation state of +2, phosphorus (P) has an oxidation state of +5, and oxygen (O) has an oxidation state of -2. The sum of the oxidation states for each element in the compound must equal zero due to its neutrality.
SnCl3? The anion SnCl3- exists and in it Sn has an oxidation number of +2
The oxidation state of carbon in C2O4^2- is +3. This is because oxygen usually has an oxidation state of -2, and the total charge of the ion is -2. By setting up the equation x(2) + 4(-2) = -2, you can solve for x= +3 for the carbon atom.
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
C2O42-COO -lCOO -O always has an oxidation states of -2.So if there are 4 O atoms, with -2 each, it gives a total of -8.since the charge on the ion is -2, the total carbon is +6, and there are 2, so each carbon is +3.C= +3
The oxidation state of hydrogen in HC2O4 is +1, and the oxidation state of carbon in C2O4 is +3. This is because the overall charge of HC2O4 is 0.
In the oxalate ion (C2O4^2-), each carbon atom has an oxidation number of +3, and each oxygen atom has an oxidation number of -2. The net charge of -2 on the ion results in an overall oxidation number of -2.
The oxidation number of Ca in CaC2O4 is +2 because Ca, a group 2 element, typically has a +2 oxidation state in compounds. The oxidation number of C in C2O4 is +3 because the overall charge of the oxalate ion is -2, and there are two C atoms, each with an oxidation state of +3 to balance the charge.
The oxidation number of C in C2O4^2- is +3. This is because each O atom is assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two C atoms must have a total oxidation number of +6 in order to balance the charge.
+3
C2O4 has a charge of -2
The oxidation state of calcium in calcium hydride is +2, as calcium typically forms ionic compounds with a +2 oxidation state.
The oxidation state of calcium is +2.
The oxidation state of carbon in methanol (CH3OH) is +2. This is because oxygen has an oxidation state of -2 and hydrogen has an oxidation state of +1, so the carbon must have an oxidation state of +2 to balance the charges in the molecule.