What is the oxidation state of C2O4 2?

Answer 1

by assuming oxalate ion. Oxalate is reducing agent and consist of2 carbon and 4oxygen , Oxygen has oxidation No:-2 and in Oxalate it becomes 4*-2=-8

and carbon has oxidation No:+3 also 2 carbon present in the oxalate ion therefor equal to =+6.

C2O4 -2

+3*2-2*4=-2

Answer 2

2.(+1 for each H) + 2.(x for each C) + 4.(-2 for each O) = Charge of ion/molecule = 0

So when 2.1 + 2.x -4.2 = 0

x = (8-2)/2 = +3

x is the calculated (mean) value of oxidation state of both carbon atoms in H2C2O4

Answer 3

An oxalic acid molecule has overall oxidation number of 0. The oxidation number of carbon is +4 (four covalent bonds per atom with oxygen). The oxidation numbers of oxygen and hydrogen are -2 and +1 respectively.

Answer 4

Carbon oxidation = -4

Hydrogen oxidation = +1

Answer 5

the oxidation of c = 1

Answer 6

-3