B2 (O2)2 (OH)4
+12 -8 -4
going off this i'd say boron's O.S is +6
The oxidation state of the cupric ion in copper tartarate is +2. Copper (II) ion, or cupric ion, has an oxidation state of +2 due to the loss of 2 electrons. In the case of copper tartarate, the ligand (tartarate) does not affect the oxidation state of the central copper ion.
The oxidation state of chlorine in the ClO- ion is 1+
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
The oxidation state of Boron in BO3^-3 is +3. This is because the overall charge of the ion is -3, and each oxygen atom has an oxidation state of -2. Hence, the Boron atom must have an oxidation state of +3 to balance the charges.
The oxidation state of the cupric ion in copper tartarate is +2. Copper (II) ion, or cupric ion, has an oxidation state of +2 due to the loss of 2 electrons. In the case of copper tartarate, the ligand (tartarate) does not affect the oxidation state of the central copper ion.
The oxidation state for oxygen in the oxide ion (O2-) is -2. Oxygen typically has an oxidation state of -2 in most of its compounds.
The oxidation state of chlorine in the ClO- ion is 1+
The oxidation state of oxygen in the hydroxide ion (OH-) is -2.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.
The oxidation state of the hydroxide ion (OH-) in a chemical compound is -1.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.
The oxidation state of manganese (Mn) in the ion Mn2+ is +2. This indicates that manganese has lost two electrons compared to its neutral state, where it has an oxidation state of 0. In compounds, the oxidation state can vary, but for the Mn2+ ion specifically, it is definitively +2.
-1 oxidation state. This ion should be called Kallide