B2 (O2)2 (OH)4
+12 -8 -4
going off this i'd say boron's O.S is +6
The oxidation state of the cupric ion in copper tartarate is +2. Copper (II) ion, or cupric ion, has an oxidation state of +2 due to the loss of 2 electrons. In the case of copper tartarate, the ligand (tartarate) does not affect the oxidation state of the central copper ion.
The oxidation state of chlorine in the ClO- ion is 1+
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
The oxidation state of Boron in BO3^-3 is +3. This is because the overall charge of the ion is -3, and each oxygen atom has an oxidation state of -2. Hence, the Boron atom must have an oxidation state of +3 to balance the charges.
The oxidation state of the cupric ion in copper tartarate is +2. Copper (II) ion, or cupric ion, has an oxidation state of +2 due to the loss of 2 electrons. In the case of copper tartarate, the ligand (tartarate) does not affect the oxidation state of the central copper ion.
The oxidation state for oxygen in the oxide ion (O2-) is -2. Oxygen typically has an oxidation state of -2 in most of its compounds.
The oxidation state of chlorine in the ClO- ion is 1+
The oxidation state of oxygen in the hydroxide ion (OH-) is -2.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
The oxidation state of the hydroxide ion (OH-) in a chemical compound is -1.
Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.
The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.
The silver ion is Ag+ and has the oxidation state of +1.
-1 oxidation state. This ion should be called Kallide