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The sulfate ion is SO42 -. The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.

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Kaleb Becker

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3y ago

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What is the oxidation state of an individual sulfur atom in (SO3)2?

If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.


What is the oxidation state for s in SO3?

The oxidation state for sulfur (S) in SO3 is +6. Each oxygen atom in SO3 has an oxidation state of -2, and since the overall molecule is neutral, the sum of the oxidation states must equal zero. Therefore, sulfur must have an oxidation state of +6 to balance the -6 from the three oxygen atoms.


What are the oxidation numbers of SO3?

In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.


What is the oxidation number for Na2SO3?

The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.


What is the oxidation state for s in (SO3)2?

S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.


What is the oxidation state for s in SO3-2?

S has an oxidation state of +4 in a sulfite anion as stated. In oxyanions, oxygen always has an oxidation state of -2. Therefore, three oxygen atoms will have total oxidation number of -6, requiring an oxidation number of +4 for sulfur to sum to the charge of -2 on the anion as a whole.


What is the valency of sulphur in SO3?

Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.


What is the oxidation number for SO3?

When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard). Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6 Since SO3 is a neutrally charged molecule, overall oxidation is '0'. Hence S + -6 = 0 Hence S = 6 is the oxudation number for sulphur. NB Sulphur exhibits different oxidation states in different molecules. S = 0 SO2 = 4 SO3 = 6 ( as above) H2SO4) = 6 H2S2O7 (Oleum) = 6


Oxidation number for each element in SO3?

In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.


What is the oxidation for S?

That depends on the compound that it is in but it is often found in the oxidation states 2-, 4+, and 6+. In its elemental for the oxidation state is 0, which is true of all elements. In sulfides, thiols, and similar compounds such as H2S, K2S, CH3SH and HSCN it s int the 2- oxidation state. In sulfur dioxide (SO2) and sulfites such as Na2SO3 and SrSO3 it is in the 4+ oxidation state. In sulfur trioxide (SO3), sulfuric acid (H2SO4), and sulfates such as MgSO4, K2SO4, and NaHSO4 it is in the 6+ oxidation state..


What is the oxidation number of the sulphur atom in SO3?

The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.


What is the oxidation of SO2?

S = +4 oxidation state O = -2 oxidation state