That depends on the compound that it is in but it is often found in the oxidation states 2-, 4+, and 6+. In its elemental for the oxidation state is 0, which is true of all elements.
In sulfides, thiols, and similar compounds such as H2S, K2S, CH3SH and HSCN it s int the 2- oxidation state.
In sulfur dioxide (SO2) and sulfites such as Na2SO3 and SrSO3 it is in the 4+ oxidation state.
In sulfur trioxide (SO3), sulfuric acid (H2SO4), and sulfates such as MgSO4, K2SO4, and NaHSO4 it is in the 6+ oxidation state..
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
S = +4 oxidation state O = -2 oxidation state
Oxidation state of O is -2.Oxidation state of S is +4.
The oxidation state of sulfur in a thiosulfate ion is + 2.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
+6 oxidation state
The oxidation number of S in S8 is ZERO!
In S2O82-, each S atom has an oxidation number of +5. In SO42-, the oxidation number of S is also +5. There is no change in oxidation number for sulfur when transitioning from S2O82- to SO42-.
The oxidation number of S in S2 is -2. Because each S atom carries a charge of -1.
In HgS the oxidation numbers are Hg +2 and S -2