[OH-][H+] = 10-14
[H+] = 10-14/0.01
[H+] = 1.0 × 10-12
pH = -log[H+]
pH = -log 1.0 × 10-12
pH = 12
formula for neutralizatrion is volume of acid X normality of acid = volume of base X normality of base so (0.3)(3) should equal (4)(volume) which is .225L. However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2. Thus, the answer becomes .1125L or 112.5ml.
When you raise the pH by adding aqueous NaOH after a precipitate forms in a solution of aqueous sodium benzoate due to a pH decrease, the precipitate likely dissolves. This is because sodium benzoate is the conjugate base of benzoic acid, so at higher pH levels, it remains in solution. The sodium benzoate will revert back to being fully soluble in its aqueous form.
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
When just enough strong acid (e.g. HCl) is used to neutralize a strong base (NaOH), the pH should be neutral (pH = 7.0).
The pH of a 50% solution of sodium hydroxide (NaOH) and water would be around 13. Sodium hydroxide is a strong base, so when dissolved in water it will result in a highly alkaline solution with a high pH value.
The pH of a 1 millimolar NaOH solution is approximately 11. The concentration of a 1 millimolar solution is 0.001 mol/L, and NaOH is a strong base that completely dissociates in water to produce hydroxide ions, leading to a basic pH.
You dont - adding NaOH increases pH.
The pH of a 0.001N NaOH solution is around 11.9. NaOH is a strong base, and at this concentration, it will result in a highly alkaline solution.
The pH of pepsin in NaOH would depend on the concentration of NaOH added. Pepsin is an enzyme that functions best at acidic pH levels, around pH 2.0. Adding NaOH, a base, would increase the pH, potentially inactivating the pepsin enzyme as it moves away from its optimal pH range for activity.
The pH of a 0.5N NaOH solution would be around 14. NaOH is a strong base that dissociates completely in water to form hydroxide ions, which contribute to the high pH value.
HCl : makes it acidic. it decreases the pH NaOH : makes it alkaline. it increases the pH
The pH of a 0.002M solution of NaOH is around 11.98. This is because NaOH is a strong base that dissociates completely in water to produce hydroxide ions, which lead to the alkaline pH.
As NaOH is a strong base I would not be surprised to see a 14 pH at least.
The pH of a 0.1M NaOH solution is around 13. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, leading to a highly alkaline environment with a high pH value.
The pH of 0.1 M NaOH is approximately 13, as NaOH is a strong base that fully dissociates in water to produce hydroxide ions. The pH of 0.05 M NaOH would also be approximately 13, as the concentration of the base does not impact the basicity significantly when dealing with strong bases.
The amount of NaOH needed to raise the pH from 8 to 10 depends heavily on the conditions. The amount of NaOH needed will increase as the volume of the solution increases. Even more importantly, buffers can stabilize the pH significantly. If buffers are presently, the pH change will be much more gradual, and more NaOH will be required.
The pH of a solution of NaOH (sodium hydroxide) is approximately 14, as it is a strong base. This means it is highly alkaline.