10
It depends on the molarity of the solution
A solution of sodium hydroxide in water will have a pH greater than 7, typically ranging from 12 to 14. Sodium hydroxide is a strong base that dissociates completely in water to produce hydroxide ions, leading to a high pH.
The concentration of the solution can be calculated by dividing the mass of the solute (12 grams) by the volume of the solution (3.3 mL) and converting to the appropriate units. This will give you the concentration of ammonium sulfite in grams per milliliter.
The initial amount of KCl in the solution is 12mL (12% of 100mL). When 200mL of water is added, the total volume becomes 300mL. You would then divide the initial amount of KCl (12mL) by the total volume (300mL) and multiply by 100 to get the final concentration of KCl in the solution.
n=c/v n=3M/.25L n=12 mol m=Mxn m=58.443 g/mol x 12 mol m=701.3 g n= mol c=concentration v=volume m=mass M= molar mass Tylerops: I don't agree with this answer. Molarity is defined as Moles/Liters. In other words Molarity is the concentration of a solution. In the above n= Concentration / Liters. That is equal to saying Moles=(Moles/liters)/ Liters. In the above question the concentration is (3 moles/ liter), or 3M. Plus, how can it be possible to have 12 moles in 250ml when you only have 3 moles in each liter of the original solution? Correct ANSWER: 3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles. 58.443g/molNaCl x .75 moles = FINAL ANSWER 43.83225g NaCl, Sig Fig, 43.83gNaCl
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
In a solution of pH of 2, there is more hydrogen ions then hydroxide ions because hydroxide ions only form with a pH pf 7 or more.Note: There are comments associated with this question. See the Discuss:What_can_you_say_about_the_amount_of_hydrogen_ions_relative_to_the_amount_of_hydrogen_ions_in_a_solution_that_has_a_pH_of_2to add to the conversation.
since it is a strong alkali its pH value will be 12-14 Depending on the concentration: 1% solution- ph12 10% solution- ph13 50% solution- ph14
The OH- concentration of ammonium hydroxide depends on its dissociation in water. Ammonium hydroxide (NH4OH) partially dissociates to form ammonia (NH3) and hydroxide ions (OH-). The concentration of OH- ions can be determined by the dissociation constant of ammonium hydroxide.
The pH of a solution with a hydrogen ion concentration of 10^-12 M is 12. pH is calculated as -log[H+], where [H+] is the concentration of hydrogen ions in moles per liter. A hydrogen ion concentration of 10^-12 M corresponds to a pH of 12.
The pH of a solution with an H+ concentration of 7.0 x 10^-12 is 11.15. This is calculated by taking the negative logarithm (to base 10) of the H+ concentration.
pH 12 is a measure of how acidic or basic a solution is on a scale of 0 to 14. A pH of 12 indicates that the solution is highly basic, with a high concentration of hydroxide ions. It is considered to be very alkaline.
1/1011.27 = 5.370 x 10 -12 ============
The pH of a solution with a hydrogen ion concentration of 7.0 x 10^-12 is 11.15. This is calculated by taking the negative logarithm of the hydrogen ion concentration (-log[H+]).
The solution has become 100 times more basic. This is because each unit increase in pH represents a 10-fold increase in the concentration of hydroxide ions, so a two-unit increase from pH 10 to pH 12 results in a 10 x 10 = 100-fold increase in basicity.
A strong alkali is expected to have a high pH, typically ranging from 10 to 14 on the pH scale. This indicates that the solution is highly basic and has a high concentration of hydroxide ions.
- log(2.7 X 10 -3 M HCl)= 2.568614 - 2.5686= 11.4314===========now,1/10(11.4314)= 3.7 X 10 - 12 M OH -=================