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pH=-log[H+]

pH=-log[1.00x10^-5M]

pH=5

When concentration of H+ is 1M, the pH is zero. Every time the concentration is decreased by a magnitude of 10 (i.e. 10^1 ---> 10^-2) the pH goes up 1 value. This is true for the pH of bases as well, but in that case pH=14+log[OH-], which is derived from pOH=-log[OH] and pH+pOH=14. This is true for pure water at 25 degrees Celsius.

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12y ago
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12y ago

[OH-] = 1e-12

pOH = 12

pH = 2

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9y ago

By definition pH = -log [H+] (in water) so the answer is found by calculation of:

pH = -log [1.2 * 10-2] = 1.92

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15y ago

pH = -log[H] = -log(1.0 x 10^-5) = 5

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4y ago

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Q: What is the pH of a solution with a hydroxide concentration OH of 1.0 x 10 12 M?
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