5 * 10**-12 mol
32 * 10**-9 mol
Concentration (M) * Volume (L) = mols
C1*V1=C2*V2
(5*10**-12)*V1=(32*10**-9)*V2
(5*10**-12)*V1/(32*10**-9)=V2
(5*10**-3)*V1/32=V2
The volume of the 5 picomolar solution that you wish take = V1
The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2
Take V2, and place into graduated cylinder and fill to V1.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
Denpending of the concentrations, you can use only mechanical agitation and elevate temperature for 5 to 15 minutes.
Mayer reagent (for narcotic alkaloids) "... can be created by dissolving 1.358 grams of HgCl2 in 60 milliliters of water, and pouring that solution into a solution of 5 grams of KI in 10 milliliters of water." (quoted from patentstorm)
5 mg of an element or compound in 1 L of solution
Preparation of standards Prepare a stock uric acid solution of 100 mg/L. Dilute it to give working concentrations of 10, 20, 30, 40, 50 and 60 mg/L. Procedure:1 Prepare a 100 mg/L stock solution of uric acid Weigh out 100 mg uric acid, transfer it to a 1 L volumetric flash, add about 900 ml distilled water, and then add about 100 µl of 0.6 N NaOH to help dissolve the uric acid. Make up to the volume with water when uric acid is fully dissolved.2 Dilute the stock solution to give working concentrations of 10, 20, 30, 40, 50, 60 mg/L. To prepare 50 ml of the working standards 5, 10, 20, 30, 40, 50 mg/L respectively, weigh 10, 15, 20, 25, 30 g of stock solution into 50 ml volumetric flasks and make up to volume with distilled water.
take 15ml od dettol solution and add into 285 ml of water . then you wll get 5% of dettol solution
ask your teacher.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
0.02/5=0.004
520 ml of HCl in 480 ml of water=1000ml = 5 N
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
What is the required concentration of it? 5 ml of 1%, 10% ? Otherwise the answer would not make any sense.
The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)
Denpending of the concentrations, you can use only mechanical agitation and elevate temperature for 5 to 15 minutes.
10g/200ml=5g/100ml = 5% solution. Now read your Dosage and Calculations book and prepare for the test because it is Monday. Good luck!