520 ml of HCl in 480 ml of water=1000ml = 5 N
6g Tris HCl + 100ml dH2O, pH 6.8
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
25 mL
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
Mix approx. 12 mL of HCl 30 % in 1 L water.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
Yes, it is possible to prepare oxalic acid by adding hcl to a solution og sodum oxalate. The balance equation would be C2O4Na2 + 2HCl -----> 2NaCl + C2O4H2.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
Add 200 mls of the 1.0N HCl solution to a 1 liter volumetric flask. Make up to the mark with water. Standardize against a known weight of Sodium Carbonate.