Silver chloride (AgCl) gives a white precipitate.
Silver Bromide (AgBr) also gives a white precipitate, though it's a slightly more creamy white than the precipitate formed by AgCl.
Silver iodide (AgI) gives a pale yellow precipitate.
When barium chloride reacts with silver acetate, a white precipitate of silver chloride is formed, along with barium acetate remaining in solution. This is because silver chloride is insoluble in water, while barium acetate is soluble.
The precipitate formed from the reaction between silver nitrate and potassium chloride is white in color. This precipitate is silver chloride, which is insoluble in water and forms when the silver ions from silver nitrate react with chloride ions from potassium chloride.
You can determine which ions are present in the water sample by conducting specific tests for each ion. For nitrate ions, you can use a nitrate test kit that typically involves a colorimetric reaction. For chloride ions, an addition of silver nitrate solution will form a white precipitate of silver chloride. Sulfate ions can be detected by adding barium chloride solution, yielding a white precipitate of barium sulfate.
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One way to separate silver chloride from barium chloride is by adding sodium chromate solution. Silver chloride will form a red precipitate while barium chloride will not react. The precipitate can then be filtered out to separate the two compounds.
When silver nitrate is added to barium chloride, a white precipitate of silver chloride forms because silver chloride is insoluble in water. This occurs due to a double displacement reaction where the silver ions from silver nitrate react with the chloride ions from barium chloride to form silver chloride. The remaining solution would contain barium nitrate as the other product of the reaction.
Some examples of simple precipitation reactions include mixing silver nitrate with sodium chloride to form silver chloride precipitate, mixing lead nitrate with potassium iodide to form lead iodide precipitate, and mixing barium chloride with sodium sulfate to form barium sulfate precipitate.
Nothing - barium chloride is soluble. You can however precipitate either the barium (e.g. with sodium sulphate, giving barium sulpate, or the chloride, e.g. with silver nitrate giving silver chloride precipitate.
an example of a precipitate is: silver nitrate + sodium chloride = silver chloride and sodium nitrate the precipitate is the silver chloride it forms a white powder
9.11 g
The precipitate formed from silver nitrate and ammonium chloride is silver chloride. This reaction occurs because silver chloride is insoluble in water.
The balanced chemical equation for this reaction is: BaCl2 (aq) + 2AgNO3 (aq) → 2AgCl (s) + Ba(NO3)2 (aq). Silver chloride is insoluble in water and forms a white precipitate, while barium nitrate remains in solution.
Silver nitrate (AgNO3) is commonly used to precipitate chloride ions as silver chloride (AgCl) in a chemical reaction. When a solution containing chloride ions is mixed with silver nitrate, a white precipitate of silver chloride forms.
The precipitate formed when silver nitrate and iron chloride are mixed is silver chloride (AgCl). Silver chloride is insoluble in water and appears as a white precipitate when the two solutions are combined.
When barium chloride reacts with silver acetate, a white precipitate of silver chloride is formed, along with barium acetate remaining in solution. This is because silver chloride is insoluble in water, while barium acetate is soluble.
The precipitate formed from the reaction between silver nitrate and potassium chloride is white in color. This precipitate is silver chloride, which is insoluble in water and forms when the silver ions from silver nitrate react with chloride ions from potassium chloride.
You can determine which ions are present in the water sample by conducting specific tests for each ion. For nitrate ions, you can use a nitrate test kit that typically involves a colorimetric reaction. For chloride ions, an addition of silver nitrate solution will form a white precipitate of silver chloride. Sulfate ions can be detected by adding barium chloride solution, yielding a white precipitate of barium sulfate.