cl2 kbr---kcl br2
i think u mean balance it right ^^;
here u have cl2 kbr---kcl br2 so what u do is
cl2 kbr---kcl br2
cl=2 cl=1
k=1 k=1
br=1 br=2
so u need to balance that ...u need to add (2) to kbr and add (2) to kcl so that u have Cl2 (2)KBr ----(2)KCl Br2 hope that will help ^^ so now u have them balanced by adding 2 in front of kbr that means u r multiplying them by 2 so that K is going to be k=2 and br is going to be br=2 and u r doing that because there is br =1 on one side and the other side there is br=2 and u need them balanced. By adding 2 to kcl means that the other k now is k=2 so as cl. hope its helpful ^____~
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
The balanced chemical equation for the reaction between chlorine (Cl2) and bromine (Br2) is: Cl2 + Br2 -> 2ClBr
2KBr + Cl2 ----> 2KCl + Br2
Bromine is diatomic, so 2 atoms make up Bromine as a reactant. Mg + Br2 ----> MgBr2
The equation for the reaction between bromine and potassium chloride is: 2KCl + Br2 -> 2KBr + Cl2
To calculate percentage yield, first determine the theoretical yield using the stoichiometry of the reaction: 1 mol Cl2 produces 1 mol Br2, so 200 g Cl2 is equivalent to 3.125 mol Br2. The molar mass of Br2 is 159.808 g/mol, so the theoretical yield is 159.808 g/mol * 3.125 mol = 499.4 g. Then, divide the actual yield (410 g) by the theoretical yield (499.4 g) and multiply by 100 to get the percentage yield: (410 g / 499.4 g) * 100 = 82%.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
MgBr2 + Cl2 yields MgCl2 + Br2 is an example of an anionic single replacement chemical reaction.
KCl: 2K(s) + Cl2(g) -> 2KCl(s) Br2: Br2(l) -> 2Br(s)
The mole ratio of Cl2 to Br2 in the given reaction is 1:1. This means that for every 1 mole of Cl2 that reacts, 1 mole of Br2 is also involved in the reaction.
When potassium bromide (KBr) reacts with chlorine gas (Cl2), it forms potassium chloride (KCl) and bromine (Br2). This reaction is a redox reaction, with bromide ions being oxidized to bromine gas and chlorine being reduced to chloride ions.
Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)
I2 is deep purple color. Br2 is a reddish brown, Cl2 is a green. F2 is yellow.
The balanced chemical equation for the reaction between chlorine (Cl2) and bromine (Br2) is: Cl2 + Br2 -> 2ClBr
2KBr + Cl2 ----> 2KCl + Br2
Bromine is diatomic, so 2 atoms make up Bromine as a reactant. Mg + Br2 ----> MgBr2
The most correct product formed from the reaction of LiBr + Cl2 is LiCl + Br2. This is because lithium chloride (LiCl) and bromine (Br2) are the expected products when lithium bromide (LiBr) reacts with chlorine (Cl2) in a single displacement reaction.